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Unformatted text preview: Name: Physics 121, Dr. Callahan Summer I 2008, Midterm #3 Note: Show your work. Clarity counts. You may use one 8 1 2 11 sheet of notes (both sides) and a calculator. 1 2 3 1. A 3.4 kg mass moving north at 1 . 5 m / s hits and sticks to a 5.0 kg mass moving southwest (45 west of south) at 2 . 3 m / s. The collision is completely inelastic. Find the magnitude and direction of the final velocity of the combined masses. Answer: Let x point east and y point north. The x and ycomponents of momentum are conserved. Thus m 1 v 10 x + m 2 v 20 x = ( m 1 + m 2 ) v fx , so v fx = m 1 v 10 x + m 2 v 20 x m 1 + m 2 = (3 . 4 kg)(0 m / s) (5 . 0 kg)(2 . 3 m / s) sin 45 (3 . 4 kg) + (5 . 0 kg) = . 97 m / s . Similarly, m 1 v 10 y + m 2 v 20 y = ( m 1 + m 2 ) v fy , so v fy = m 1 v 10 y + m 2 v 20 y m 1 + m 2 = (3 . 4 kg)(1 . 5 m / s) (5 . 0 kg)(2 . 3 m / s) cos 45 (3 . 4 kg) + (5 . 0 kg) = . 36 m / s ....
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This note was uploaded on 07/12/2008 for the course PHY 121 taught by Professor Chamberlin during the Spring '08 term at ASU.
 Spring '08
 Chamberlin
 Mass, Work

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