math 202 lesson #2 - We No’res#Z—Finding The derivative...

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Unformatted text preview: We; No’res #Z—Finding The derivative of The inverse If f(x) is the original function and fL1 (x) is the inverse and you want the derivative ofthe inverse which is 4'_1 (f )(v)—f,(x) L flM=Jx+1 fimfi/”(m)' i “wmmw ewe w 3 ga;12k§WX“§”§ : 5%.“? E .4”) ff” _ _ ~W-W M ‘ 8 Ageixii i- u “ mwmww em »w av 3g“, «5%: Mi “Q g :3: 2nmmwumwmgfimy E ffig $12: : W i is x a; “wwwwm. :r Ljifi flyifixefiwggxwig §X%§i g 6’ Xfii 3. If f(x)=x5+5x-4 find ( f ”I (2))' ; j X. :73 <3” 53:; x W ‘4? . ©::x§ifixwe exiie IX; 3: 3; WM i; 3 , fix»; f i 4. If f(x)=x5+2x +1 find (f"1(4))' _ i .9, 4 a Lifififliex+i _ 7 3 W {g G g: x g” ism m3 3"“;6‘3? «m icy/j Xe} W "7T 72- ’ _1 5. ff =2t d—<x<—fmd 2 ' (x) anx an 2 2 (f ()) i2 “3: 2. *niflflr/K 1 / 4 Ewr%fi%fl X 1": “E % 6. 13300333 x>o find(f_1(6))' £33135 X?“ (331:: 313 M #3331 3333i 3* 3“ ; § M '33 33; ~33 31 3313333 33 33 343 33’ 7 L31 f1 3:31 :3: 33 3.13 If 33 131 1113 111333333333 111113313311 61‘ 3‘Z 3111.131 33 3'3) {:3 3X3: “3X :WWme 3 “’3: 1:3 X3 3X 2 3 X33 3 :13 X: 3 : 1311131 33; {213 1111313: 0131 11113 1111313332 1311323132311 13f ,3 3:11}: 3:5 —:1i321 9 ‘ 3 /f3 RX (.2 :3 X 11.11 X3 “3’2” X m :1: fr.“ $3.1 3:; 3 X: 33:; X: 3- :32: >3 ”2 f) X :13» 3 1‘12” ”321’; K:%i:/J: ,X“: 1 11 3—13—2325 and f (5:):«éZ 1113331 gT—E): fil 9 3 3 ”WW :: If f(0)_ ~— M 31111:; (O): 6 111131 (Fl) (~31 10. x 1 - 1 331171) 21:3; :1 Wm:..m”’fl”/f ...
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