This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: LS4 Midterm I INSTR: L. Johnson Monday, Jan. 31, 2005 NAME:_________________________________ (last) (first) I.D. #__________________________________ INSTRUCTIONS 1. This exam is 6 pages long. Problem Value Score Before starting make sure you have all the pages. 1 12 2. Be sure to write clearly. Only 2 14 legible answers will be graded. 3 7 4 9 5 1 4 6 1 2 7 1 8 8 14 Total 100 KEY 1 NAME:_________________________________ ID# _______________________ (last) (first) (12 pts) 1. In Drosophila, the dumpy mutation gives rise to short, oblique wings. The ebony mutation is characterized by ebony-colored body. Both of these are autosomal recessive alleles. Determine the genotypes of the flies that are crossed below by analyzing the phenotypic ratios of the offspring. Be sure to use Drosophila nomenclature and indicate the alleles for both dumpy and ebony. Assume homozygosity unless there is evidence to the contrary. a) wild type female x wild type male Æ ¾ wild type, ¼ dumpy e+e+ dp+dp x e+e+ dp+dp (+4) b) dumpy female x wild type male Æ 3/8 dumpy, 1/8 dumpy ebony, 3/8 wild type, 1/8 ebony e+e dpdp x e+e dp+dp (+4) c) wild type female x wild type male Æ 1/16 dumpy ebony, 9/16 wildtype, 3/16 ebony, 3/16 dumpy, e+e dp+dp x e+e dp+dp (+4) (14 pts) 2. a) In tomatoes, three independently assorting genes determine whether the fruit is red (R) or yellow (r), the shape is normal (O) or oblate (o), and the skin is smooth (P) or peach (p). Using the branch diagram, determine all the phenotypes and their ratios for the progeny resulting from the following cross: (+8) Rr oo Pp x Rr Oo Pp ¾ P- Æ 9/32 red normal smooth...
View Full Document
This note was uploaded on 07/13/2008 for the course LS 4 taught by Professor Ribaya during the Spring '08 term at UCLA.
- Spring '08