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mmle1key - I ECE 3041 Exam No.1 THURSDAY JUNE 3 6 PM GTID...

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I ECE 3041 Exam No.1 Summer 2004 THURSDAY JUNE 3, 6 PM GTID No.9 Name ~ Instructions. Totally Closed Book and Note. Calculator Permitted. Four Equally Weighted Problems. All Work Must Be Shown for Credit. 1. Determine the percentage error due to dc ammeter loading in the measurement of the dc current Ix in the circuit shown below. The ammeter has an internal resistance or input impedance of 7.3 o. As an intermediate step in the solution determine the Thevenin equivalent circuit with respect to the ammeter. 1mA ~ 50 150 1a 0 1a 0 50 1amY - E;m~ 10 S((lS +20- l51/(\$1-10) _/r 10 51(15:12M1V t; t- {D + SUI S ~ + (S It( I" 1'"S) I 0 + s + 5[115 «~::: 1 D + l 5 {} 5 I { (5 t-ID") = 13..D- i<:.?tJ ~ :::: - too . R~ - = - 3S,Cf6/~ «~ + ~~ 5 Eth = 5 Rth = ~ % error = \2tW1V 13 -D- -36 '7~ t"l1(" \ 0 ~"

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r . 2. Determine the percentage error due to dc voltmeter loading in the measurement of the dc voltage VAAl in the circuit shownbelow. The dc voltmeter is a SimpsonMeter Model 260-7 set to the range just larger than the Thevenin voltage with respect to the voltmeter. The available ranges for the Simpson meter are lV, 2.5V, @, 50V, 250V, 500V, and 1, OOOV. As an intermediate step in the solution determine the Thevenin equivalent circuit with respect to the meter. 8mA 5k 0 10kO 6mA v ~;::; J 0 ;V R~::: {5 V~;;. 2oCiSL J p') .' \I Z OJ:;/ ~-IL 12kO II 10 V 15kO A A' o-;o~ :::. <a . S. . S+":?JjISi-IO+12 311 ( 5+12-+1t/) 311 (~-tI2..+IO) -+-\.; 31\ \ S\\C S tl2. NO] == 2..2 '6lr~ RoJ1 it... +R.~ t ~ t ~ 3111 S - b 10 lD+3TrlS +5-+-12- - '3 ~. 2 2.1. \J sltlS \ -::';01 - -\0 - R~ ::; >r I () 0 - - - lOr) 2..'2.~~ 2, L... '8'15"-+ 200 -1.L~ ,. ';'0 7 Eth = -:3 ~ 2.2 V } Rth = 2... 2. q ~ 7 % error = ~3;" 0 ~'"* <:r \O~d 2
3. Determine the percentage error due to ac voltmeter loading in the measurement of the rIllSmagnitude of the ac voltage VAA' in the circuit shown below. The ac voltmeter is a

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mmle1key - I ECE 3041 Exam No.1 THURSDAY JUNE 3 6 PM GTID...

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