pH Practice Problems

pH Practice Problems - 7. 10.0 mL of 0.020 M NaNO 3 + 20.0...

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pH Practice Problems Describe the system below and how to find the pH; Single Component Solutions: 1. 0.010 M Rb I 2. 0.010 M NH 4 OH K b =1.8x10 - 5 ( ) 3. 0.010 M HNO 2 K 2 = 5.1x10 - 4 ( ) 4. 0.010 M KF K a = 6.7x10 - 4 ( ) Two Component Solutions: 1. 15.0 mL of 0.010 M HNO 2 K a = 5.1x10 - 4 ( ) + 10.0 mL of 0.010 M KOH 2. 10.0 mL of 0.020 M HNO 2 K a = 5.1x10 - 4 ( ) + 20.0 mL of 0.010 M KOH 3. 15.0 mL of 0.010 M HNO 2 K a = 5.1x10 - 4 ( ) + 10.0 mL of 0.020 M KOH 4. 15.0 mL of 0.010 M HNO 3 + 10.0 mL of 0.010 M KOH 5. 10.0 mL of 0.020 M HNO 3 + 20.0 mL of 0.010 M KOH 6. 10.0 mL of 0.020 M HNO 3 + 20.0 mL of 0.010 M CsNO 3
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pH Practice Problems Describe the system below and how to find the pH (continued);
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Unformatted text preview: 7. 10.0 mL of 0.020 M NaNO 3 + 20.0 mL of 0.010 M MgCl 2 8. 15.0 mL of 0.010 M HNO 3 + 10.0 mL of 0.020 M KOH 9. 15.0 mL of 0.010 M NH 4 OH K b =1.8x10- 5 ( ) + 10.0 mL of 0.010 M KOH 10. 15.0 mL of 0.010 M NH 4 OH K b =1.8x10- 5 ( ) + 10.0 mL of 0.010 M HCl 11. 15.0 mL of 0.010 M NH 4 OH K b =1.8x10- 5 ( ) + 10.0 mL of 0.010 M HNO 3 12. 15.0 mL of 0.010 M NaNO 2 K a = 5.1x10- 4 ( ) + 10.0 mL of 0.010 M KCl 13. 15.0 mL of 0.010 M HNO 2 K a = 5.1x10- 4 ( ) + 10.0 mL of 0.010 M RbNO 2 14. 15.0 mL of 0.010 M KF K a = 6.7x10- 4 ( ) + 10.0 mL of 0.010 M KOH...
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This note was uploaded on 07/14/2008 for the course CHEM 103 taught by Professor Kramer during the Fall '08 term at University of Delaware.

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pH Practice Problems - 7. 10.0 mL of 0.020 M NaNO 3 + 20.0...

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