202 Lab Report 2 Questions

# 202 Lab Report 2 Questions - 3 Area of Steel =.05842 in2 a...

This preview shows pages 1–2. Sign up to view the full content.

3. Area of Steel = .05842 in 2 Area of Aluminum = .0632 in 2 a. Ours: Steel: Slope = 1.429*10 6 lb/in At 1000 lb: displacement = 1000 lb / 1.429*10 6 lb/in = 6.998*10 -4 in Stress at 1000 lb: 1000lb /.05842 in 2 = 17.12 ksi Strain at 1000 lb: displacement / initial length = 6.998*10 -4 in / 7 in = 9.997 * 10 -5 Young’s modulus: 17.12 ksi / 9.997*10 -5 = 171.23 Mpsi Aluminum: Slope = 6.67*10 5 lb/in At 1000 lb: displacement = 1000 lb / 6.67*10 5 lb/in = 1.499*10 -3 in Stress at 1000 lb: 1000lb /.0632 in 2 = 15.82 ksi Strain at 1000 lb: displacement / initial length = 1.499*10 -3 in / 7 in = 2.141 * 10 -4 Young’s modulus: 15.82 ksi / 2.141*10 -5 = 73.90 Mpsi Average: Steel: Slope = 1.392*10 6 lb/in At 1000 lb: displacement = 1000 lb / 1.392*10 6 lb/in = 7.163*10 -4 in Stress at 1000 lb: 1000lb /.05842 in 2 = 17.12 ksi Strain at 1000 lb: displacement / initial length = 7.163*10 -4 in / 7 in = 1.023 * 10 -4 Young’s modulus: 17.12 ksi / 1.023*10 -4 = 167.30 Mpsi Aluminum: Slope = 6.003*10 5 lb/in At 1000 lb: displacement = 1000 lb / 6.003*10 5 lb/in = 1.666*10 -3 in Stress at 1000 lb: 1000lb /.0632 in 2 = 15.82 ksi Strain at 1000 lb: displacement / initial length = 1.666*10 -3 in / 7 in = 2.380 * 10 -4 Young’s modulus: 15.82 ksi / 2.380*10 -4 = 66.48 Mpsi b. Our Max Stress of Steel: (5719 lb. / .05842 in 2 ) = 97.89 ksi Our Max Stress of Aluminum: (2819.2 lb. / .0632 in 2 ) = 44.61 ksi Average Max Stress of Steel: (5590.28 lb. / .05842 in 2 ) = 95.69 ksi Average Max Stress of Aluminum: (3043.62 lb. / .0632 in 2 ) = 48.15 ksi c. Yield Load for Aluminum = 2400 lbs. Yield load for Steel = 4000 lbs.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern