phy 131 final with solutions

Phy 131 final with - R y = 2.58 10 3 N 160 12.7 12.7 8.43 8.43 2 35.5 8.07 8.07 7.66 7.66 6.13-6.13 6.13 t=1.34 s 7.66 1.34 6.16

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1200 !/ (a) Torque with respect to point P is zero: " 2000 l sin 25 o ( ) " 1200 l 2 sin 25 o ( ) + T 3 4 l sin 90 o ( ) = 0 T = 1.47 # 10 3 N ( b ) F x = 0 " R x # $ T cos(25) = 0 R x = 1.47 % 10 3 0.906 " R x = 1.33 % 10 3 N F y = 0 " R y # + T sin(25) $ 2000 $ 1200 = 0 R y = 3200 $ 1.47 % 10 3 0.423 "
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Unformatted text preview: R y = 2.58 % 10 3 N 160 12.7 12.7 8.43 8.43 2 35.5 8.07 8.07 7.66 7.66 6.13-6.13 6.13 t=1.34 s 7.66 1.34 6.16...
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This note was uploaded on 03/10/2008 for the course PHY 131 taught by Professor N/a during the Winter '07 term at Cal Poly Pomona.

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Phy 131 final with - R y = 2.58 10 3 N 160 12.7 12.7 8.43 8.43 2 35.5 8.07 8.07 7.66 7.66 6.13-6.13 6.13 t=1.34 s 7.66 1.34 6.16

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