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# solution4_pdf - ig996 Homework 4 Lyon(53565 This print-out...

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ig996 – Homework 4 – Lyon – (53565) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. This HW asignment is due Wednesday, ±eb. 13, by 4:00PM. 001 10.0 points When the chemical reaction A + B C + D is at equilibrium, 1. both the Forward and reverse reactions have stopped. 2. the Forward reaction has stopped. 3. the reverse reaction has stopped. 4. all Four concentrations are equal. 5. the sum oF the concentrations oF A and B equals the sum oF the concentrations oF C and D. 6. neither the Forward nor the reverse reac- tions have stopped. correct Explanation: Chemical equilibrium is dynamic equilib- rium, with both Foward and reverse processes occuring at the same rate. 002 10.0 points In which oF the Following cases will the LEAST time be required to arrive at equilibrium? K below reFers to the equilibrium constant. 1. Cannot tell since the time to arrive at equilibrium does not depend on K . correct 2. K is a very large number. 3. Cannot tell without knowing the value oF K . 4. K is about 1. 5. K is a very small number. Explanation: The equilibrium constant K re²ects the relative amounts oF products and reactants present when the reaction is complete, and gives no inFormation on the time needed. The rate constant k indicates how Fast the reaction occurs. 003 10.0 points Consider the reaction 2 SO 2 (g) + O 2 (g) 2 SO 3 (g) . At equilibrium at a certain temperature, the concentrations oF SO 3 (g), SO 2 (g), and O 2 (g) are 0.12 M, 0.86 M, and 0.33 M, respectively. Calculate the value oF K c For this reaction. 1. 0.87 2. 0.42 3. 1.31 4. 0.014 5. 0.059 correct Explanation: 004 10.0 points Write the equilibrium expression For the reac- tion SbCl 5 (g) SbCl 3 (g) + Cl 2 (g) 1. K = P SbCl 5 P SbCl 3 P Cl 2 2. K = P SbCl 3 P 2 Cl 2 P 2 SbCl 5 3. K = P SbCl 3 P SbCl 5 P Cl 2 4. K = P SbCl 3 P Cl 2 P SbCl 5 correct 5. K = P 2 SbCl 3 P Cl 2 P SbCl 5

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ig996 – Homework 4 – Lyon – (53565) 2 Explanation: Since this is a gas phase reaction, K is the ratio of the partial equilibrium pressures of the products to the partial equilibrium pres- sures of the reactants. 005 10.0 points What would be the expression for K c for the reaction 4 NH 3 (g) + 5 O 2 (g) 4 NO(g) + 6 H 2 O(g) at equilibrium? 1.
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solution4_pdf - ig996 Homework 4 Lyon(53565 This print-out...

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