2008_05_30_14_27_34

2008_05_30_14_27_34 - CHEM l l — Fall Quarter 2007 Dr...

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Unformatted text preview: CHEM l l — Fall Quarter 2007 Dr. DiPasqttalc Exam 2 DO NOT OPEN THIS EXAM UNTIL YOU ARE TOLD TO [)0 SO!!! There are 20 questions worth 2.5 points each. You will have 50 minutes to complete the exam. Your answers will be submitted and recorded using your lntchrite PRS RF clicker. Your electronically submitted answers are what will be scored. so please make sure you input your answers properly and in the units requested. Do not submit answers in scientific notation as they will not be correctly scored. You may submit an answer for any question as many times as you wish within the time period for the exam. but only your last response fora given question will be retained. A Periodic Table with useful constants and an equation sheet are attached. Feel free to write on this exam for your work. CLICKER lNSTRUCTlONS: I. Join the RF class as you normally would by finding the class name or by typing the channel number noted on the chalkboard. 2. The top line 01‘ your clicker should display “TST:” which indicates you are in test mode {see below}. raw—mu“- *‘—— ---.--~—-—---v—--r-o—-—-t-r——w—--——-—--———-v- ——r---w—----.--—-—--—--——-:-v-.-—-—. El a _ |s=terw-_I__te i It ‘t FRS l I . Lu When asked to "Enter Test ii". please enter your test form. This is form 1). Press "’ and you will get a “Received” confirmation. If"Enter Test it" is not displayed or ifyou entered the wrong test form. press the ( button while "TST:" is diSplayed to change your test form. '4. Use the A and Y buttons to navigate to the question number you want to answer. You may answer the questions in any order at your own pace. Answer with either a numerical ansuer or A thru ii for multiple choice questions. Press "’ and you will get a “Receix-ed" confirmation. When you have submitted all ol‘ your answers and are finished with your exam. turn your clicker off inside ofthe lecture hall and do not turn it back on until after the exam has concluded or your submitted answers may be erase’ . 'JI TST: D fie VSEPR model or molecular structure requires a knowledge of to predict the geometry 0 fan atom in a molecule. A) the total number of atoms in the molecule B) the number of atoms bonded to the atom of interest C) the number of electron pairs on the alum of interest D} both A and C E) none of the above 2) The value for A for an atom containing 4? protons, 47 electrons, and 60 neutrons is 2) /3)’If the elements W, X, Y, and Z have electronegativity values of 1.0, 2.0, 2.5, and 3.5, respectively, which bond is ionic? 1/5 A) WY B) wz ( (fix D) xz E) XY ,4) The element least likely to obey the octet rule in forming chemical-bonds is A) nitrogen. B) neon. C) fluorine. - I Dljcarbon. E) oxygen. \ ,JC\ 5) Thewelement with the electron configuration 1522522p63523p5 is A)‘chlorine. B) sulfur. C) carbon. D) potassium. E) fluorine. \_ } “ D—l nD fiie name of Sn2+ is ion or ion. 6] A} lin(l]; stannous B) tin; stannous C) tin(II); slannic D) tintll); stannous ’fflinfl); stannic Magnesium is an example of a{an) 7) A) halogen. \{EJ noble gas. C) alkaline earth. \IJ.) transition metal. < Nalkali metal. A: ‘ 8} The atomic number of an atom containing 4? protons, 4? electrons, and 60 neutrons is 8] 9) The l-lCO3' ion is: called 9) “k 5 A) hydrogen carbide B) carbonate C) carbide D) hydrogen carbonate ii) carbonile DAZ E'G Mag/(x0 10 M10113 11101 pun ‘sn1011d5011d .10 1110113 31.10 '113301p1iq1o swam 31113;“: ’u330111u1o smom 331111131 "1,. ‘suouaap 13.11313 x15 put? ‘uaBA’xo ‘" 10 su10112 11101 ’snqusoqd 10 111011: auo 113801qu 10 sum“: an1am1 'u380111u10 51110112 33.1111 [(1 'uaBAxo 10 :u101e mo; pun ’smoquoqd 30 5111011! 11101 'uafimp/(q 10 511.101? an1am1 ‘uafionw 1o swam 331111 (f) 'uafiflxo / 10 51110112 11101 pue “5111011515qu 10 1110119 91.10 ‘uaflm p/(L1 10 511.1011? 311131111 ‘uaflm11u 10 11.10113 auq/(g 'uafiflxfo 10 91.110112 11101111112 “smoquoqd 10 wow aun “11.180.1qu 10 5111019 uanas 113301111110 911.1012 33.1111 (1/ l? (<51 10 pasodmoa 51 13111101111103 51111 10 111m 11111111101 auu 113111 531E31pu11?0d£(tr1.11\1) 121an 3111 (£1 41 HTJ “(C 1'2 f1 PM ’111 “as (a 3v '11 ’0d {a 1d ’Pd ‘IN {3 5v “as 15121 1121 “ax ’J>1 (v (31 gs1uaLua1a >1301q—p ri1uo 5u1121u03 dnmfi 1131111111 anoqe 31.1110 31101.1 (1] H3H ((1 H-H (j 3H (a H=H (V {11 51301103 101191 31113310111 11380113511 e10 uo11121uasaJdaJ 113111M {[1 .--'1 M {Jr um1pos 11111111111 ‘11380113511 (11 u1n11muuafi ‘sruoquoqd ‘uafifixo (a au110n11 ’uaBAxo ‘u330111u (D au1u101q ‘1n11n5 “1133011111 (EL - 1.103.112 ‘uoau 1111111311 (V (0]; gsa1ma1om 311110112113 512191113 Aneuuou 113111111 s111au131a A1uo su1e1uoa anJB 113111M 1 protons and neutrons. B) 35, 17 @172 18 2/ 14) Atoms of 13C] contain A1121? [3018,17 ‘l l orbitals, and up to M3, 6,12 /B)’3,12,36 film shell having 11 = 3(cg'mlains subspells, \I B) 6, 18 /C} 2, 4, 8 \‘-. f; 1“ 16) Which of the following elements is most likely to form an ion with a —-2 charge? A) Ti B} Si C) Mg D) 5 +1 \ “7L :1 My ' \\ \\\\ .jl\ ' 4 7E‘Bzf (E '2'), H‘) 72:, Which of the following subshells consists of three orbitals? A} 4d @115 C) 4f D) 4p E) none of the above E) 35, 18 14) electrons. 15} E) 3, 9, 18 2,) 3} 8) 17) main group element E reacts with chlorine to form an ionic compound with the formuia EClg. 18) Th e element E is a member of what group in the Periodic 'l‘abie? :QF6A B) 7A . 51?: n W 3' “I E) none of the above {3 l (a fit '_ Cl - Ti ‘ flaw.“ is the maximum number of electrons that can occupy the 4p orbitals? I9) )— 4, J 20) One characteristic of a cation is 20) A) it has equal numbers of protons and electrons. B) the relationship between protons and electrons varies with the cation in question. £2 it has more electrons than protons. LD}.-it has more protons than electrons. E) the number of neutrons is related to the number of electrons. Equation Sheet Chemical Foundations Sf:fl 90.: {1", -32°F} 0 F ._ r,=an xfimzr n = 1} r m. I5 Mill l Dr'n.u'1‘_\.' = min mr Stoichiumetry Him “In : _ mam 010:1: molt: uf substance unlual yieid [:1 + x 1009; Ihmrcllcal yield 1F] i‘emrnl yicld :— rrmies of while L1tliflnl}'[LIJ:———-—T— \ alumni: of onLIlmu {L1 51'. .-. .3}... J = Mp.-......-L'r..-.....a States of Matter furrr Pres hure : dfl'fl flf.’ T, _. ."i' = nh‘j‘ JRT muiur mm; : _— P P.“ = 11+}: raw RT ‘ P, M. .- rrlw.[ -—_ } 1' __ n. It. : _. HI.... I P=Lflm .‘Ri‘ \I mutur mun Rafa rJf Efflurrm fur guy i _ Jnrm’ur mm. 2 Ram of :jfiuimr fiar 2m 2 mm’ar man i i [154“:[315 ‘IXH” —H.b} —_ :rkt' ml— Idsini} . AH. I ' -_-__'..'L .— ‘ mum} R [TJH : AH 1 1‘ lawn-J f'. R T_. 1'. mass at clement in I molt: (If substance x1009} Thermochemistry fifzq vii-:q—PA'.’ work = fierce w (imam? Av = VI“... = 1.1“. u'=—PA':’ an =fiEt-I'AV q : rm 3T qufiT a H = mat... ~ H at: mmmmprrjmm ' A H = qr A: mmram mimic .' a E = q, 5 H 2 r Zn, 3 “If, f'rmtrrcu J — Err, a H}! Revert-mum .-‘\ G“ : En“ A G;I{P(fldrd{!fi i — z!”r a Gflflrurmnhj A5" : 212:5": .i'me-ujv— Zn__$‘[h'rurmnn] 3 = it In“? 'g“-|n «I =_fl ... .. T git-“,3 T :56 =AH—TAS 30° — Mitts? A! rquffifin'rrm a G" = U rfrrr'lfnn’ A H : = T d5° P d 1' Ar; = A6“ + RT [nQ where Q _- fl .‘t‘rnrrurm A: tqtrihbnrrm :3 U" = -RT In K __ mo 1 a._s_° W‘— H Electrnchemistry 5.1-- = 5:1“... - E" - 5L- '— 5;.” + 5.1%... war].- llJ') rul‘wrgc {Ci t‘frurgr : flu" .5 U" = —HF.E‘7 R'.’ F. : E“ ~-—| J HF mi 0050 E: 5“ - liogQ at “5°C :1 {‘mrmmm n; dram! : amp! X .u't'muir Properties of Solutions mass of saint: I ma.” 0)“ militia"; Mam perrrm = l x IlIi'FF: ,H'm'r frat'lr'rm (If A = x1 : —”‘ "mm! nmmn 5 t: M .‘rfnia'n'n'z ——_ I u {rim Minimum "Mun." : moles fifmfwr ' “toga-am: nfsuirm: C = k? = PM. = I: + is fiP..-...... -' 1' 3”. l‘wr'r Hut? farior 1f): _ mum (If mimr dumb-ed a T : inner” .51" = IKImM“ II = {MET Nuclear Chemistry Rah-'2 —‘—h—‘—.EN m 1n[%]:-tr :3 5 = :3 m": Structure and Bonding :‘= il' AH =."rr F _ 81' w... — "I E : "er: I! : iml‘ {2.0. ] r .E = (2.3I K IU"‘Jm-rr)[ Lam'u' mergr = hf G'Q' ] \ r [‘uimiumi dippia mrmmulm = Q x r mmmred dipntr mnmrnr rgf x- i" t'nii'm’med dipnir mnme'ul nf x'i" 'K- hmrr :[ A H : 2 Utbmrd; broken] — 2 Divasz formed] 1' . _. Fm! ring : {minus a" i‘ :l‘hrmdt'ng r'i-mmrboudmi; :1 ,1 main nf pum'ci'm in mhm'r‘n x "119‘: Chemical Kinetics firm = -M = Ely-l Ar A! Ram = A-[AHBI' Jnm =~u+1nldl1 [A]. . 1n[F~]=—LI [ 1: .ir L “hi-h Chemical Equilibrium A; =K,[RT)" ash—mm pH +p0fl' = 1-1 [H' Hair}: 10'“ pi! = ulugLH'] H’ :1— K, = [ml {wr‘ 0H- X" [Ll dirmriarrd Ufmrri'aiirm = {urinal} KNK, = K_ = 10'“ pK" + pkr : I4 HI if _ m = mg + loath-1] = M, + log[ [ [Buffer]=[ii'] fr] K," = Ir'nnmrl' [animrr [Raul {‘ [.4 rd} 1 ...
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2008_05_30_14_27_34 - CHEM l l — Fall Quarter 2007 Dr...

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