hwenzym - =(Abs 30 sec – Abs 15 sec(60sec(cm.mole(3.0 x...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
2) Data table : Absorbance measured at 340nm Run # Abs 15sec Abs 30sec RU (min -1) Velocity (µmole/ min.mL) 1 0.114 0.348 936 4.51 2 0.748 1.039 1164 5.61 3 0.758 0.957 796 3.84 4 0.971 1.232 1044 5.04 5 0.667 0.913 984 4.75 6 0.871 1.145 1096 5.29 7 0.683 0.989 1224 5.90 8 0.851 1.065 856 4.13 9 0.568 0.812 976 4.71 10 0.513 0.710 788 3.80 Average run# 6-10 988 4.76 +/- 0.238 a) RU for run #1 Racker units (RU) = (change in absorbance) (60sec) x 1000 (change in time) (1 min) = (0.348 – 0.114) (60sec) x 1000 (30sec – 15 sec) (1 min) = 936 b) Velocity of run #1 Velocity = (change in absorbance) (60sec) 1 volume of assay 1 1 x 10 6 µmole (change in time) (1 min) volume of NAD Ɛ + path length 1 mole
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = (Abs 30 sec – Abs 15 sec ) (60sec) (cm.mole) (3.0 x 10-3 L) 1 1 x 10 6 µmole (30 sec – 15 sec) (1 min) (6220 L) (0.1 mL) (1.00 cm) 1 mole = (0.348- 0.114) (60sec) (cm.mole) (3.0 x 10-3 L) 1 1 x 10 6 µmole (30 sec – 15 sec) (1 min) (6220 L) (0.1 mL) (1.00 cm) 1 mole = 4.51µmole/min.mL c) RU average calculation RU average = ∑(Ru of runs# 6-10) 5 = (1096 + 1224 + 856 + 976 + 788) 5 = 988 d) Velocity average calculation Velocity average = ∑(Velocity of runs# 6-10) 5 = ( 5.29 + 5.90 + 4.13 + 4.71 + 3.80) 5 = 4.77 µmole/min.mL...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern