122ch13c_001

# 122ch13c_001 - mass CH 3 OH mass CH 3 OH = x 100 total mass...

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27 13.34) Note the denominator in mass % is the total mass of solution Total mass = mass solute + mass solvent Technically, the total mass in part b is: 1000 g H 2 O + 0.0079 g Sr 2+ = 1000.0079 g soln ppm = (0.0079 g Sr 2+ )/(1000.0079 g soln) x 10 6 = 7.8999 = 7.9 ppm Since the amount of Sr 2+ is so minute compared to the amount of H 2 O there was no problem in ignoring it in the denominator in part b above.

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28 13.35) A solution contains 14.6 g CH 3 OH in 184 g H 2 O. a) Find mol fraction of CH 3 OH, X CH3OH mol CH 3 OH X CH3OH = ----------------------- (No unit) total mol solution 1 mol CH 3 OH ? mol CH 3 OH = 14.6 g CH 3 OH x --------------------- = 0.45 5 6 mol CH 3 OH 32.04 g CH 3 OH 1 mol H 2 O ? mol H 2 O = 184 g H 2 O x ------------------ = 10. 1 2 mol H 2 O 18.016 g H 2 O 0.45 5 6 mol CH 3 OH X CH3OH = --------------------------------- = 0.042 7 1 = 0.0427 (0.45 5 6 + 10. 1 2) mol soln b) Find mass % CH 3 OH (also called wt % or wt/wt %)

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Unformatted text preview: mass CH 3 OH mass % CH 3 OH = ------------------------ x 100% total mass solution 14.6 g CH 3 OH mass % CH 3 OH = ------------------------------------- x 100% (14.6 g CH 3 OH + 184 g H 2 O) = 7.3 5 14 % = 7.35 % CH 3 OH c) Find molality of CH 3 OH, m mol CH 3 OH m = -----------------kg H 2 O 0.45 5 6 mol CH 3 OH m = -------------------------- = 2.4 7 65 = 2.48 m CH 3 OH 0.184 kg H 2 O 29 13.37) mol solute molarity, M = ---------------L solution a) mol Mg(NO 3 ) 2 0.540 g Mg(NO 3 ) 2 1 mol Mg(NO 3 ) 2 10 3 mL soln ? ------------------- = ------------------------ x ------------------------- x ----------------L soln 250.0 mL soln 148.31 g Mg(NO 3 ) 2 1 L soln = 0.01456 M = 0.0146 M Mg(NO 3 ) 2 30 31 13.44) 32 13.46) 33 13.46) (cont.) 34 13.48) 35 13.48) (cont.) 36 13.48) (cont.)...
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122ch13c_001 - mass CH 3 OH mass CH 3 OH = x 100 total mass...

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