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hmwk_3b3 - 78 Pan ELEM 27.—————————(L...

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Unformatted text preview: 78 Pan ELEM 27. .._.—————————#*' (L) CLH‘L may, 0, = 2Cl'l.dila.m3 = 7.4.07.1:3.“ Mass H = 1CI.OOSQM;‘) = 2.0lbmm Paw:- mm -. 719.0331WU-L McL‘aS "7; c __ mm, "‘00 - _«-_i___________.ozz QWU-L loo = 92.2577: MMC Z.(.O3BCLWL 5) mafia H -.~ 8 0.09%1m3 = 8.DC='-l m PM = 2 (fiber-n ‘) + 80-0083 + 32.0% + 40551934) = 6'2.qu Mass '7; H .-. (“n55 H “‘00 = [3-094 0mm. ]loo : (c.1037. MhJ \‘5‘2.Hlu.mm c) Mass 0 z (octagon-43 = CiSHfitoq <3.ng Fu.) —. 6302.0” 3 + 2-1 0.0083 + $059934) = $11154 Mm Mass '7, o = [0:5ch m ] loo : 49.9320 ”Z, \Q'llSLl mm; W— d) Mash P+ = mama am’ Put} —_ mac-:3. + ~l (35.4521) + 104-000 3+ 6: (Loos) = 370950 Mass "To PC —. [Wlwo : 52.58871 3103'50mm a) Mass C = 1802 .cm 3 = 2mm am «Mass -— HammouU-r 7.4 0.0083 + ZUSHQ‘H) = 212.341 um ’1']?— . '5“! mm Mass "70 C. 2 [2160.10 amu]1¢° 3 "H.312 ‘79 PROBLEM 50 a.) H-000 =3 CEwo-L’I‘LB) 7.": b) (9.017.,‘IO «dams , ~23- C) \‘1.000 g i \ Mo‘ _____ __ 1 [3331. ID 3 mo 1 c. 97.7. .. to“ aims ...
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