hmwk_3b4 - t i i PeoeLem 32 Ho lb ’1\K i(5.022...

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Unformatted text preview: ; t i i # ; PeoeLem 32 Ho lb ’1 \K; i (5.022.: lea-‘1' \Dmu‘a : ALI-I x '01.“! k3/ bu.“ ”2.2-qu ”D \mlo. bu.“$ Ml This is 3‘”; a. “H.124, \ofl qulLu-IWM "WA Mose a? M Wm. PROBLEM ‘54 a) mm = G. (won 31mm « lo (Loo‘aslmogar tiqqqnl Slmo‘ + 2(32.o¢°(a In = 1:92.21“? (blano‘ b) 5.00me5,‘ \% * \mo\ taoauo‘smd 1000 ms “31.277 5 _ 7. C.) 5.08 n 10 smo ‘ («J—[“3052 ,‘ (a 5:317— “ IolgmoknaLLa‘S = L 8651. ‘02 “Loraine: ‘ MO‘ (:3qu 052 a) Leading: CeHmOSL ,‘ Am , 3.11 “to“ 5 Jam; \mhmu Ce, H u, as; PczoeLEM '58 a.) (3.557 30414.1)2005 5‘ \moL. (NH-{vtCoa “ I‘M-ates MPH-l, ___ gong, ll €19.09 3 mm, 51cc), lmb. “1‘4ch05 53 0.0438 mo‘ FEPOLI ,. w :- (a.{¢\ 3/FQPO.‘ lnno‘ FePO...‘ c3 zmutoflmwub cheo ,.. ‘w‘ CaHsm ,. lawn : 80.5 c H6 4 (cannon Mamba. 7:15—55- 3 d3 Mu) : v3.8a: g = 284."! 3/mol ooSS'lOml PROE>LEM '46 a) 0.191.! ma‘ K 4.. ‘1 EmPidK-gfl Fo—rma-L‘l z W1C05 0.062 Po+u551mm augmd‘e. 0.057. MD‘ C 4. ‘ 0.052 ...
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