q2w.key - Dr. Zellmer Time: 23 mins Name 1. KEY Chemistry...

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Chemistry 101 Wednesday 9:30 AM Time: 23 mins Summer Quarter 2008 July 2, 2008 Quiz II Name KEY Rec. Instr. 1. (5 pts) The specific gravity of ethylene glycol is 1.1088. What volume (in L) of ethylene glycol is required to provide 1.125 kg? You MUST use the factor unit method to receive full credit ! density of substance Specific Gravity is “same” as density, but no unit sp. grav. = ---------------------------- density of water (D H2O = 1.0 g/mL for most purposes) ˆ D EG = 1.1088 g/mL (use this a conversion factor between mass and volume of ethylene glycol, EG) (5 s.f.) 1.125 kg has 4 sig. fig. and 1.1088 g/mL has 5 sig. fig. so the answer has 4 sig. fig. All other conversions are exact by definition. (Just for your information, 1.1088 g/mL =1.1088 kg/L.) 2. (7 pts) The amount of lead, Pb, in the air on a particular day is 1.60 x 10 ! 10 lb/ft 3 ? How many grams of lead are present in 3.00 m 3 ? (1.000 lb = 453.6 g) (You MUST use the factor unit method to receive full credit
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This note was uploaded on 07/17/2008 for the course CHEM 101 taught by Professor Stegemiller during the Summer '07 term at Ohio State.

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q2w.key - Dr. Zellmer Time: 23 mins Name 1. KEY Chemistry...

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