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122ch14hout

# 122ch14hout - Chapter 14 — Kinetics Hdditional Practice...

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Unformatted text preview: Chapter 14 — Kinetics Hdditional Practice Problems 14.26 A hypothetical reaction A —t products is second order in A. The half-life of a reaction that was initially 1.66 M in A is 310 min. What is the value of the rate constant? 14.27 A reaction shows the same half-life regardless of the starting concentration of the reactant Is it a ﬁrst-order or a second-order reaction? \$0. In three different experiments the following results were obtained for the reaction A -> products: [A]() = 1.00 M, rm =‘ 50 min; [A10 = 2.00 M, (1,2 = 25 min; [Mo = 0.50 M, 1,,2 = 100 min. Write the rate equation for this reaction and indicate the value of k. 51. Ammonia decomposes on the surface of a hot tung— sten wire. Following are the half-lives that were obtained at 1100 °C for different initial concentrations of NH3: [NH3 0 = 0.0031 M, (1,2 = 7.6 min; 0.0015 M, 3.7 min; 0.00068 M, 1.7 min. For this decomposition reaction, what is (a) the order of the reaction; (b) the rate constant k? [H.641 The gas-phase reaction of chlorine with carbon monoxide to form phosgene, Clz(g)+CO(g) —t COCll(g), obeys the following rate law: A[COClz] Al Rate = = k[Clz]"‘[C0] A mechanism involving the following series of steps is con- sistent with the rate law. Ci2 = 2C1 c1+co : coct coc1+c11 2 cocn,+cn .. Assuming that this mechanism is correct, which of the steps above is the slow, or rate-determining, step? Explain. Hint: try making each step the slowest step [rate—det. step] and see what rate law you get and if it agrees w. the exp. rate law giuen. £29 5414— MLM aw gag/W __ “mg, [email protected]_ﬂ _. _. H; **** M r 9;. " ; :27 __ . _ . J24 75% ._ygtyi_fm52Z/§ fytwfj_2_i_3ﬂ__m 7,, .ﬁ.w.._.___—,;6(Q)_§_" ~__._.H_ 75.1751625m __ .7 __ 26% W _ . _. .. .. ” _ _. .. ._______ \$sz .. . Ag: .".719______.___._.m.£’[/€f t. .52) ""LT71TIT/£32221;fﬁQQLLfEiyaréézé)7iiiZ...__ ' " . __ __z,__(2.0_, .. . W,néioﬁWirWWﬁm. ________ _ 4:430. . ._ . , .. .. .. _. ._ 12/1 .. . , I '. xix. _. m fave (a? _ A 14,231.. J... J 3) " 2’55 J- __ ﬂy; 7:22121 f _ . . . _._ _. a L _ " ' "- -—~— ....___.___ i‘ é : 1% 1430. : WM? :“v .. _ .w #322277 ____.._____ I 7W2?» -=52mw¢.._.---._L;;;_;:,z,_._,,.;_;:'__i;;j;;_;_“‘ " “ . . .________§d_,éyé __._ ._ _ Q. ﬁEﬂx/JZ..._8,&X/Q__zﬂo,m1 ' 'é '- : .__ _ -_ r m— _ ‘ Bull-IWF—h-m—hu- M 65/)- fg:/;) :Kgpgil: r 3 g 25 (:1. gig 0245; " ' (if 5+) 4mggz§¢ _._____..."_H_,______.[<a_ . (:1 ﬁﬁiﬁﬂé’i , "‘ (ﬂaw Q'Aamp—ﬁgagkw "jg/m») \$577; +50%: (054; I _ f I __ Mlﬁfcaub a MUM: M _#_Mé‘ it 6.4g? 6114;114:444 - __ﬂW c? ’ rm Wm__ . . -____#£ou__,caL7;/éz_ rm. ﬂag " ' _ _____ _a _ ﬂ S‘J/gﬂ (37} fW/I— @hmé-ﬁgxéa _.._. __ _- .‘ e e s; . . ___._ SEQ). 7% 9w a'Ffm 7% , 0f- til/«42W__ __H_,“__ 440 - “CLJQ I 75'W aézﬁéé/g‘f’ 722 313:! ,7 4552915” Egg aauzsmé/ﬁéi; __ (f , -9 r: 64? M11” 64? . "' ' 5w? r01 2 Q1“ =7 EMMA—J =A;fwaj - ...
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