122ch15d - 40 15.67) Kp = Kc (RT)n Kc = Kp (RT)&)n =...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon
40 15.67) K p = K c (RT) ) n K c = K p (RT) ) n = (4.3 3 2) {(0.0821 L C atm/mol C K)(1100 K)} ( 1) = 0.047 9 68 = 0.0480
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
41 15.70)
Background image of page 2
42 15.71)
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
43 15.72)
Background image of page 4
44 15.74) Mathematical LeChatelier’s Principle Application
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
45 15.76)
Background image of page 6
46 15.77) 15.79)
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
47 15.80)
Background image of page 8
48 15.81) Both the forward and reverse reactions in the equilibrium A º B are elementary (single-step) reactions. Assume the only effect a catalyst has on the reaction is to lower the activation energies of the forward and reverse directions by the same amount (i.e. it lowers the “hill” in the reaction pathway by the same amount). Prove that the equilibrium constant for the catalyzed reaction is the same as for the uncatalyzed reaction. The catalyst only speeds up the reaction and does not effect the position of equilibrium. The amount of reactants and products at equilibrium is the same with or without a catalyst. Remember, for a reaction in which both the forward and reverse reactions are elementary reactions you can show the equilibrium constant is related to the rate
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 10
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/17/2008 for the course CHEM 122 taught by Professor Zellmer during the Summer '07 term at Ohio State.

Page1 / 11

122ch15d - 40 15.67) Kp = Kc (RT)n Kc = Kp (RT)&)n =...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online