mq2a - 1. (5 pts) Consider the reaction represented below....

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1. (5 pts) Consider the reaction represented below. C 2 H 4 Br 2 + 3 KI 6 C 2 H 4 + 2 KBr + KI 3 If the concentration of KI is decreasing at a rate of 0.807 M/min, what is the rate of change in the concentration of KBr? a) 0.134 M/min b) 0.269 M/min c) 0.404 M/min d) 0.538 M/min e) 1.21 M/min 2. (7 pts) Hydrogen sulfide is a pollutant in industrial waste waters. One method of removal is oxidation by dissolved oxygen. 2 H 2 S + O 2 6 2 S + 2 H 2 O The reaction is first order in each reactant with a rate constant of 4 x 10 ! 5 M ! 1 s ! 1 . Determine the initial rate of the reaction if concentrations in polluted water are 5 x 10 ! 6 M H 2 S and 2.6 x 10 ! 4 M O 2 . a) 3 x 10 ! 19 M/s b) 1 x 10 ! 16 M/s c) 5 x 10 ! 14 M/s d) 7 x 10 ! 12 M/s e) 2 x 10 ! 10 M/s (1) 3. (7 pts) To obtain the rate law for the following reaction, BrO 3 ! + 5 Br ! + 6 H + 6 3 Br 2 + 3 H 2 O initial concentrations of reactants were systematically varied and the initial rate of disappearance of BrO 3 ! was determined. The following data were obtained. initial concentrations initial rate exp. [BrO 3 ! ] [ B r ! ] [ H + ] M / s 0.0333 0.0667 0.100 4.68 x 10 ! 5 0.0333 0.133 0.100 9.36 x 10 ! 5 0.100 0.0667 0.100 1.41 x 10 ! 4 0.0333 0.0667 0.200 1.87 x 10 ! 4 The rate law has the form rate = k[BrO 3 ! ] x [Br ! ] y [H + ] z . The values of x, y and z are a) x = 0 y = 1 z = 1 b) x = 1 y = 1 z = 2 c) x = 2 y = 2 z = 4 d) x = 3 y = 2 z = 4 e) x = 1 y = 5 z = 6 4. (5 pts) The numerical value of the rate constant for the reaction described in the prevoius question is ______. a) 2.11 b) 52.7 c) 378 d) 702 e) 949 5. (5 pts) For the reaction represented below, 2 NO 2 (g) 6 2 NO(g) + O 2 (g) a graph of R n k versus time is a straight line with a slope of ! 0.775 s ! 1 at 40C. From this we can conclude a) rate = k[NO 2 ] 2 and k = 1.29 M ! 1 s ! 1 . b) rate = k[NO 2 ] 2 and k = 0.775 M ! 1 s ! 1 . c) rate = k[NO 2 ] and k = 0.461 s ! 1 . d) rate = k[NO 2 ] and k = 0.775 s ! 1 . e) E a = 64.4 kJ/mol. (2) 6. (7 pts) The rate constant for the first order conversion of cyclopropane to propylene is 5.40 x 10 ! 2 hr ! 1 . How many hours are required for 90.0% of the cyclopropane to react (10% remains)?...
View Full Document

Page1 / 9

mq2a - 1. (5 pts) Consider the reaction represented below....

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online