# mq2a - 1(5 pts Consider the reaction represented below C 2...

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Unformatted text preview: 1. (5 pts) Consider the reaction represented below. C 2 H 4 Br 2 + 3 KI 6 C 2 H 4 + 2 KBr + KI 3 If the concentration of KI is decreasing at a rate of 0.807 M/min, what is the rate of change in the concentration of KBr? a) 0.134 M/min b) 0.269 M/min c) 0.404 M/min d) 0.538 M/min e) 1.21 M/min 2. (7 pts) Hydrogen sulfide is a pollutant in industrial waste waters. One method of removal is oxidation by dissolved oxygen. 2 H 2 S + O 2 6 2 S + 2 H 2 O The reaction is first order in each reactant with a rate constant of 4 x 10 ! 5 M ! 1 s ! 1 . Determine the initial rate of the reaction if concentrations in polluted water are 5 x 10 ! 6 M H 2 S and 2.6 x 10 ! 4 M O 2 . a) 3 x 10 ! 19 M/s b) 1 x 10 ! 16 M/s c) 5 x 10 ! 14 M/s d) 7 x 10 ! 12 M/s e) 2 x 10 ! 10 M/s (1) 3. (7 pts) To obtain the rate law for the following reaction, BrO 3 ! + 5 Br ! + 6 H + 6 3 Br 2 + 3 H 2 O initial concentrations of reactants were systematically varied and the initial rate of disappearance of BrO 3 ! was determined. The following data were obtained. initial concentrations initial rate exp. [BrO 3 ! ] [ B r ! ] [ H + ] M / s 0.0333 0.0667 0.100 4.68 x 10 ! 5 0.0333 0.133 0.100 9.36 x 10 ! 5 0.100 0.0667 0.100 1.41 x 10 ! 4 0.0333 0.0667 0.200 1.87 x 10 ! 4 The rate law has the form rate = k[BrO 3 ! ] x [Br ! ] y [H + ] z . The values of x, y and z are a) x = 0 y = 1 z = 1 b) x = 1 y = 1 z = 2 c) x = 2 y = 2 z = 4 d) x = 3 y = 2 z = 4 e) x = 1 y = 5 z = 6 4. (5 pts) The numerical value of the rate constant for the reaction described in the prevoius question is ______. a) 2.11 b) 52.7 c) 378 d) 702 e) 949 5. (5 pts) For the reaction represented below, 2 NO 2 (g) 6 2 NO(g) + O 2 (g) a graph of R n k versus time is a straight line with a slope of ! 0.775 s ! 1 at 40°C. From this we can conclude a) rate = k[NO 2 ] 2 and k = 1.29 M ! 1 s ! 1 . b) rate = k[NO 2 ] 2 and k = 0.775 M ! 1 s ! 1 . c) rate = k[NO 2 ] and k = 0.461 s ! 1 . d) rate = k[NO 2 ] and k = 0.775 s ! 1 . e) E a = 64.4 kJ/mol. (2) 6. (7 pts) The rate constant for the first order conversion of cyclopropane to propylene is 5.40 x 10 ! 2 hr ! 1 . How many hours are required for 90.0% of the cyclopropane to react (10% remains)?...
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mq2a - 1(5 pts Consider the reaction represented below C 2...

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