# Hw4s - 5—1(Keyhani Lecture The one-line diagram of an...

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Unformatted text preview: 5—1 (Keyhani Lecture} The one-line diagram of an unloaded power system is shown below. Reaetanees of the two sections of transmission line are shown on the diagram. The generator and transformer ratings are as follows: Generator 1: 2|} MVA. [3.8 HP. X; = [LED per unit Generator 2: 3D MVA, 18 1513', X; - 0.20 per unit Generator 3: 3|] MVA. 1t] 11V. X; = H.211} per unit Transformer T1: 25 MFA, 3de 13.83: It‘r', X = lﬂ‘iﬁ Transformer T1: single-phase units, each rated 1t] MVA, 12‘? f 13 it"r'. X - 1ﬂ% Transformer T3: 35 MVA. IEDYJEEY kV. X - 10% T 1531 e 2F2 M {—uioﬁ. w‘dﬁ ﬁt) ‘1' 1'1 ﬂ El 3 4—31" a) Draw the per unit equivalent circuit with all reaetanees marked in per unit on your circuit. Choose MVA base of lﬂﬂ. h) Compute the YBUg model of the system for short-circuit studies. e) Compute the short circuit current ﬂowing through breaker A for a three-phase fault at point B. d) Compute the Yang model of the system for power ﬂow studies. Solution: a} 103 G1: yb=1ss w, X": 0.2:: -— =1.a so me T1:VM_V=13.8 kV, rampage W, In = am 'E = 0.4 2202 130 z = =4s4n, 2' =—= 13.155 ”a mo “’3‘: 434 I ma Ts: yblm=22 kV, yszsa W, In = n.1o-— = 0.235 35 ' 2 {33: Vblm=22 kv, 2'33": {1.22 (E) E = 2.55 22 3D jlﬂﬂ _ 2' = — = 2.222 ”“1“ 424 j 100 , T2: Vbﬂ=12 kV, “mama/5 x12? =22!) kV= mm”, 2n = 2.12 - E = {1.33: (32: X52": {1.20 - g = 0.552 ...
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