lecture7 - EE 740 Professor Ali Keyhani Lecture #7...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
EE 740 Professor Ali Keyhani Lecture #7 Transmission Line Parameters
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Transmission Line Parameters Circular-mil = d 2 1 mil = .001 inch 1 inch = 1000 mils A = d 2 cmil Inductance of a solid cylindrical conductor. Internal Inductance Lint = μ /8 Π H/m μ = 4 Π x 10 -7 L 1 int = ½ x 10 -7 H/m External Inductance. L 1 ext = 2 x 10 -7 ln D/r 1 H/m Total Inductance for conductor #1: L 1 = L 1 int + L 1 ext = ½ x 10 -7 + 2 x 10 -7 ln D/r 1 = 2 x 10 -7 (1/4 + ln D/r 1 ) = 2 x 10 -7 (ln 1/4 + ln D/r 1 ) = 2 x 10 -7 ln D/r 1 -1/4 = 2 x 10 -7 ln D/r’ 1 H/m Where: r’ 1 = r 1 -1/4 = 0.7788r 1 r’ 1 = G.M.R of conductor 1. d r D Conductor 1 Conductor 2 I r 2 I r 1
Background image of page 2
Capacitance of a single-phase line (two wire circuit). C 12 = ∏∈ / ln (D/r) F/m C 12 = 0.0388 / 2 log (D/r) μ F/mile Cin = 0.0388 / log (D/r) C 12 = Total circuit capacitance Cin = capacitance of one conductor to neutral Xc = 1/2 fc = 4.10/f x 10 6 log (D/r) -mile to neutral Inductance of a three phase line with equilateral spacing:
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 7

lecture7 - EE 740 Professor Ali Keyhani Lecture #7...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online