lect5 - Lecture 5 - EE743 Lecture 5 - EE743 Electromagnetic...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Lecture 5 - EE743 Lecture 5 - EE743 Electromagnetic Force and Torque Professor: Ali Keyhani Professor: Ali Keyhani 2 Electromagnetic Force and Torque Review: Review: dx d f dx d N i f dx d N i f Ni N N i L dx dL i x W f N x L i x L W W em em em c e f c - = - = = = = = = = = = = = 2 2 2 2 2 2 2 2 2 2 2 1 2 1 1 2 1 2 1 ) ( ) ( 2 1 3 Consider the electromechanical system given below, k f D m g x d Electromagnetic Force and Torque 4 Assumptions such as: The area of the center leg is twice the area of the outer legs The reluctance of the materials of the electromagnet and the plunger is neglected. Applying Amperes Law to solve the previous electromechanical system, Electromagnetic Force and Torque 5 Electromagnetic Force and Torque d x Ni H B H B d H x H Ni d d x x d x d x d d x x "d" length of airgap the in intensity Magnetic x" " length of airgap the in intensity Magnetic B B B H B H + = = = = = + = 6 Electromagnetic Force and Torque Let A: area of the center leg A/2: area of the outer leg for Solving 2 2 2 2 d x NiA d A x A Ni B B A B A B BA d x d x + = + = = = = = 7 Electromagnetic Force and Torque d x A N i N L i d x A N N + = = + = = 2 2 The equation for the electrical system is, [ ] dt dx dx x dL i dt di x L Ri V i x L dt d Ri V ) ( ) ( ) ( + + = + = 8 The mechanical system can be described by, where , g: the value of x at which the spring is relaxed. Electromagnetic Force and Torque ) ( 2 2 x x k dt dx D dt x d m f e- + + = 9 The dynamic performance of the electromagnetic system is described by two-nonlinear equations, as shown previously....
View Full Document

Page1 / 31

lect5 - Lecture 5 - EE743 Lecture 5 - EE743 Electromagnetic...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online