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# sc_prob - Eﬁ740 IL A pnerltor nappies I motor through a...

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Unformatted text preview: Eﬁ740 IL! A pnerltor nappies I motor through a Y-A transformer. The generator it connected to the Y side of the trlnﬂormer. A fault occurs between the motor terminds-and the Water. The symmetrical components of the subtransient current in the motor ﬂogging toward the fault are 1.1 = —0.8 — 12.6 per unit. I,2 = —j2.0 per unit, and 1.0 = — 1'10 per unit. From the transformer toward the fault I“ =2 0.8 —-jO.4 per unit. 1., = ~jl.0 per unit. and 1.0 =0. Assume X: 2 X2 for both the motor and the generator. Describe the type of fault. Find (a) the prefault current. if any. in line a. (b) thé lubtransient fault current in per unit, and (c) the subtransient current in each phi: of the motor in per unit. sobx‘nw \$492- qus: l“; 1:... lap} +M 3 +1.‘ Nam” (44. \$[M3Lﬁ—r W— to— 7YOUMJ WL1‘ l g! o») wwwfs ma. WYMM HM- Mwwk (Aug. éf-Hw. 4mm. .5 +1» mvvun‘ .1114. to ‘HM. Fawn” Wm ;_ 4m brmdusoé m easih‘m. -smrumu. miwwm 1‘s ‘ MSW 0L9 WW ‘Hw— bYMChLS 01! ‘HM- daejxfl‘m 1 “WW miwoflb Mm 9L“. X. Vm quad . ‘50 x2. valw-s 44: Cancun—«div bywclus. u TN- ?wﬂ3—-{‘MH_ cuNY—M" «a;- HM. W!- at. toward 17 HW- mﬁwis ? . ~ WW1} CA I MO‘UY —.~ :3 1' (“5m— '45 E ' b ﬂ§i+ww 'XC 1 /‘ W m. wit LwLﬁwL’t) . 10.71% #7:“; +1“. - . Wow“ :2; 14,29 , . ;—. I . If ‘ '3 _ A. W; «Jill-L" , IL _ ha: “7* 50 “it ‘. ] gummy? To“: M“ szﬁ' 1:45 ' ' , ‘ I ﬁt. ' ‘ sfgjatlLf o‘HPfAIW 4 h'y‘l‘u-ILL" Cu. . «hurl. “- ( P {_..1 fill/‘4‘} I“! fﬂrlb§tk «d 4.3.“ " ' "in" ”I'm" m“ MhiL‘i’ £04411th ' WW~I¢5qF I‘m-='-“3*'S -.‘+':4L1.rr.=—T\*D 3C #1 -;~ 2 WW?» 3.,ng ‘vi — 42m gm-Ef‘iwwt 3.3;. . \$95M”. "' 1“ IMF-g J 1mm: = - 8-124 “5.“ E‘- [..8‘32 £-(-32'O)‘5 “Loam: -32 O I. T‘ _,=.8+1.‘ Q‘u L w“ 'l” «Era-£9; Wﬂm - L ., With‘LV “”3"" 9“ TM " il‘ IA\=~i(o-8—3-H) =— .4 -3-8= 0‘89“ L._""" Im=j(-na) 1m: [:Aa:° Im=+§tm 1h315‘+1513'(:—30-9=\\0 [—324" 16112-3 1A1. 13‘: o. 994 L__”—3"1.° : “932410-749 ;131=\'OLBJ1°=--9+30-866 .__-_._.__..____.___..__.__._- -....._..__-. _ .-.“..me . ... .. - +- ... ... (A 1'3 = 1m+132 -—0o991+'5l'5’2 2' #8911113! 10V: o- 894 L31: :0: 89M- 3.04253 Inn-we 13.4.93- --5 550.35; 1‘- ‘1-0! +73-e:: .391 13': 813 : 0.90 3 L-éqq‘ ...
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