Nagy_BUS207.920_Ch10

Nagy_BUS207.920_Ch10 - Chris Nagy BUS207.920 Chapter 10...

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Chris Nagy BUS207.920 11/13/2007 Chapter 10, pages 361-365 #29 - 61 EOO

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29 z=1.83 33 t= -1.57 37 X=15.66 s= 1.544 t=3.40 41 X= 5.1667 s= 3.1575 t = -1.463 45 X= 1641/15=109.4 s= 9.9628 t=3.654 49 z= 1.43 53 z= 2.56 57 z= -1.14 61 50 + 2.33(10/√n)= 55- .323(10/√n) let n= 33 H 0 : μ= \$45000 H 1 : μ≠ \$45000 Reject H 0 = if z< -1.65 or z>1.65 Reject H 0 H 0 : μ≥7.0 H 1 : μ<7.0 reject H 0 if t < -1.667, assuming a 5% significance level Do Not reject H 0 H 0 : μ≤ 14 H 1 : μ> 14 Reject H 0 = if t > 2.821 Reject H 0 H 0 : μ≥ 6.5 H 1 : μ < 6.5 assuming a normal population
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Unformatted text preview: Reject H = if t < -2.718 Do Not reject H H 0 : μ≤ 100 H 1 : μ> 100, assuming a normal population Reject H = if t > 1.761 Reject H H 0 : π ≤ 0.02 H 1 : π> 0.02 Reject H = if z > 1.65 fail to reject H H 0 : π ≤ 0.44 H 1 : π> 0.44 Reject H = if z > 1.65 Reject H H 0 : π = 0.50 H 1 : π ≠ 0.50 Reject H = if z isn't between -196 and 1.96 Do Not reject H n=(5.71) 2 = 32.6...
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• Fall '07
• RHINE,S
• Business, 5%, Prime number, Green Line, \$45000, Reject H0 H0, Chris Nagy

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