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lecture15

# lecture15 - EE 205 Coifman Homework set#6 due 4-37 4-38...

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n a m f i o C 5 0 2 E E 15-1 Homework set #6, due 5/7/08 4-37, 4-38, 4-49, 5-4, 5-6, 5-9, 5-12, 5-14, 5-15, 5-19, 5-22, 5-29, 5-33, 5-34 Dynamic Circuits - Signal Waveforms v t V i t I o o ( ) = ( ) = for - < t < v(t) V 0 0 t v(t) v(t) v(t) v(t) v(t) v(t) v(t) v(t) t t t t t t t t d i o s u n i S p e t S Exponential Damped sinusoid Pulse train Square wave Sawtooth Triangular wave

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EE 205 Coifman 15-2 The Step Function ut t t () = < 00 10 , , now change the amplitude. .. Vut t Vt A A < 0 , , and the time-shift. .. Vut T tT T AS S () = < 0, , v(t) v(t) v(t) v(t) v(t) v(t) t t t t 0 t 0 0 t 0 0 V A V A V A V A V A V A T S T S T S T S T S T S V A < 0 V = 0 V > 0 T S < 0 T = 0 T > 0
EE 205 Coifman 15-3 So what else does it do? Show how the following pulse is simply the superposition of step functions. v(t) t t 3 0 3 3 0 3 1 02 3 4 5 01 2 3 4 5

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EE 205 Coifman 15-4 Unit Impulse Function. .. you gotta trust me on this one. δ t t t () = ∞= 00 0 , , and xdx ut t () = () −∞ i.e., t du t dt 1 sec v(t) t (t) (1) δ How do you change the amplitude and the time-shift for this function?
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lecture15 - EE 205 Coifman Homework set#6 due 4-37 4-38...

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