# Calc03_5 - x by using the quotient rule tan d x dx sin cos...

This preview shows pages 1–5. Sign up to view the full content.

Greg Kelly, Hanford High School, Richland, Washington Photo by Vickie Kelly, 2001 London Bridge, Lake Havasu City, Arizona 3.5 Derivatives of Trig Functions

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
π 2 π 0 2 π - π - Consider the function ( 29 sin y θ = We could make a graph of the slope: θ slope 1 - 0 1 0 1 - Now we connect the dots! The resulting curve is a cosine curve. ( 29 sin cos d x x dx =
π 2 π 0 2 π - π - We can do the same thing for ( 29 cos y θ = θ slope 0 1 0 1 - 0 The resulting curve is a sine curve that has been reflected about the x-axis. ( 29 cos sin d x x dx = -

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
We can find the derivative of tangent
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: x by using the quotient rule. tan d x dx sin cos d x dx x ( 29 2 cos cos sin sin cos x x x x x--2 2 2 cos sin cos x x x + 2 1 cos x 2 sec x ( 29 2 tan sec d x x dx = → Derivatives of the remaining trig functions can be determined the same way. sin cos d x x dx = cos sin d x x dx = -2 tan sec d x x dx = 2 cot csc d x x dx = -sec sec tan d x x x dx = csc csc cot d x x x dx = -π...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern