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Phys 181b Chapter 32 Solutions

# Phys 181b Chapter 32 Solutions - 1(a The flux through the...

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1. (a) The flux through the top is + (0.30 T) π r 2 where r = 0.020 m. The flux through the bottom is + 0.70 mWb as given in the problem statement. Since the net flux must be zero then the flux through the sides must be negative and exactly cancel the total of the previously mentioned fluxes. Thus (in magnitude) the flux though the sides is 1.1 mWb. (b) The fact that it is negative means it is inward.

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16. (a) From Eq. 32-10, ( ) ( ) ( ) ( ) ( ) 5 4 4 0 0 0 0 2 12 2 2 4 2 8 4.0 10 6.0 10 6.0 10 V m s C 8.85 10 4.0 10 m 6.0 10 V m s N m 2.1 10 A. E d d dE d i A A t A dt dt dt ε ε ε ε Φ ª º = = × × = − × ¬ ¼ § · = − × × × ¨ ¸ © ¹ = − × Thus, the magnitude of the displacement current is 8 | | 2.1 10 A. d i = × (b) The negative sign in d i implies that the direction is downward. (c) If one draws a counterclockwise circular loop s around the plates, then according to Eq. 32-18 s d B ds i z = < G G µ 0 0, which means that G G B ds < 0 . Thus G B must be clockwise.
18. (a) Since i = i d (Eq. 32-15) then the portion of displacement current enclosed is i i R i d R , .

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