Phys 181b Problem Set 2 Solutions

Phys 181b Problem Set 2 Solutions - 3 The following diagram...

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3. The following diagram is an edge view of the disk and shows the field lines above it. Near the disk, the lines are perpendicular to the surface and since the disk is uniformly charged, the lines are uniformly distributed over the surface. Far away from the disk, the lines are like those of a single point charge (the charge on the disk). Extended back to the disk (along the dotted lines of the diagram) they intersect at the center of the disk. If the disk is positively charged, the lines are directed outward from the disk. If the disk is negatively charged, they are directed inward toward the disk. A similar set of lines is associated with the region below the disk.
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5. Since the magnitude of the electric field produced by a point charge q is given by 2 0 | |/ 4 E q r πε = , where r is the distance from the charge to the point where the field has magnitude E , the magnitude of the charge is ( ) ( ) 2 2 11 0 9 2 2 0.50m 2.0 N C 4 5.6 10 C. 8.99 10 N m C q r E ε = π = = × ×
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8. (a) The individual magnitudes G E 1 and G E 2 are figured from Eq. 22-3, where the absolute value signs for q 2 are unnecessary since this charge is positive. Whether we add the magnitudes or subtract them depends on if G E 1 is in the same, or opposite, direction as G E 2 . At points left of q 1 (on the – x axis) the fields point in opposite directions, but there is no possibility of cancellation (zero net field) since G E 1 is everywhere bigger than G E 2 in this region. In the region between the charges (0 < x < L
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