BENG 449 Problem 7 1

# BENG 449 Problem 7 1 - 4/3/08 5:34 PM MATLAB Command Window...

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4/3/08 5:34 PM MATLAB Command Window 1 of 2 >> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % Alex Lemon % % BENG 449 -- Biomedial Data Analysis % % Problem Set 7, Question 1 % % Due April 4th, 2008 % %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % Suppose that a ligand, L, binds to two different binding sites, B1 and % B2, with dissociation constants Kd1 and Kd2 respectively, and total % concentrations Bmax1 and Bmax2 respectively. Then the total bound ligand % concentrations is: % B = Bmax1 * L / (Kd1 + L) + Bmax2 * L / (Kd2 + L). % Assume that Bmax1 and Bmax2 are equal and Kd1 = 1 nM. Plot B vs. log L % for 5 Kd2 values over the range from 1 to 100 nM. Bmax1 = 0.5; Bmax2 = 0.5; Kd1 = 1; LogKd2 = 0:0.5:2; L = 0:1:1000; legend_strings = cell( length(LogKd2), 1 ); figure(length(LogKd2) + 1); title( strcat( texlabel('Bound Ligand Concentration'), . .. texlabel(' versus Free Ligand Concentration') ) ); xlabel( texlabel('Log Free Ligand Concentration, log L') ); ylabel( texlabel('Bound Ligand Concentration, B') );

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## This note was uploaded on 07/19/2008 for the course BENG 449 taught by Professor Richardcarson during the Spring '08 term at Yale.

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BENG 449 Problem 7 1 - 4/3/08 5:34 PM MATLAB Command Window...

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