Phys 181b Problem Set 11 Solution

Phys 181b Problem Set 11 Solution - 2. (a) The frequency of...

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2. (a) The frequency of yellow sodium light is f c == × × λ 2 998 10 589 10 509 10 8 9 14 . . ms m Hz. (b) When traveling through the glass, its wavelength is λ λ n n = 589 152 388 nm nm. . (c) The light speed when traveling through the glass is () ( ) 14 9 8 5.09 10 Hz 388 10 m 1.97 10 m s. n vf ==× × = × λ
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13. (a) We choose a horizontal x axis with its origin at the left edge of the plastic. Between x = 0 and x = L 2 the phase difference is that given by Eq. 35-11 (with L in that equation replaced with L 2 ). Between x = L 2 and x = L 1 the phase difference is given by an expression similar to Eq. 35-11 but with L replaced with L 1 L 2 and n 2 replaced with 1 (since the top ray in Fig. 35-36 is now traveling through air, which has index of refraction approximately equal to 1). Thus, combining these phase differences and letting all lengths be in µ m (so λ = 0.600), we have L nn LL n 2 21 12 1 1 350 0 600 160 140 400 350 0 600 1 140 0833 λλ −+ −= + b g b g b g b g . . .. . . (b) Since the answer in part (a) is closer to an integer than to a half-integer, the interference is more nearly constructive than destructive.
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19. The condition for a maximum in the two-slit interference pattern is
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Phys 181b Problem Set 11 Solution - 2. (a) The frequency of...

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