This preview shows page 1. Sign up to view the full content.
Unformatted text preview: (a) x 2 3 (mod 11 2 23 2 ) (b) x 2 9 (mod 2 3 3 5 2 ) 4. From 7 2 1 (mod 5 2 ), nd a solution to x 2 1 (mod 5 3 ). 5. Evaluate the Jacobi symbol ( 12 35 ) . How many solutions does x 2 12 (mod 35) have? 1...
View
Full
Document
This note was uploaded on 07/23/2008 for the course MATH 465 taught by Professor Yee during the Spring '08 term at Pennsylvania State University, University Park.
 Spring '08
 YEE
 Number Theory, Congruence

Click to edit the document details