CHAPTER 13 HOMEWORK KEY

CHAPTER 13 HOMEWORK KEY - CHAPTER 13 HOMEWORK KEY 20. For...

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1 CHAPTER 13 HOMEWORK KEY 20. For the reaction: H 2 (g) + Br 2 (g) 2 HBr (g) , K p = 3.5 x 10 4 at 1495 K. What is the value of K p for the following reactions at 1495 K? a. HBr (g) ½ H 2 (g) + ½ Br 2 (g) b. 2 HBr (g) H 2 (g) + Br 2 (g) c. ½ H 2 (g) + ½ Br 2 (g) HBr (g) 26. The following equilibrium pressures were observed at a certain temperature for the reaction: N 2 (g) + 3 H 2 (g) 2 NH 3 (g) P NH3 = 3.1 x 10 -2 atm, P N2 = 8.5 x 10 -1 atm, P H2 = 3.1 x 10 -3 atm. Calculate the calue of the equilibrium constant K p at this temperature. If P N2 = 0.525 atm, P NH3 = 0.0167 atm, and P H2 = 0.00761 atm, does this represent a system at equilibrium?
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2 32. In a study of the reaction: 3 Fe (s) + 4 H 2 O (g) Fe 2 O 4 (s) + 4 H 2 (g) at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0 torr, that total pressure at equilibrium is 36.3 torr. Calculate the value of K p for this reaction at 1200 K. Hint : Apply Dalton’s law of partial pressures.
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3 36. Ethyl acetate is synthesized in a nonreacting solvent (not water) according to the following
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This note was uploaded on 07/22/2008 for the course CHEM 105A taught by Professor Bau during the Summer '04 term at USC.

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CHAPTER 13 HOMEWORK KEY - CHAPTER 13 HOMEWORK KEY 20. For...

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