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Unformatted text preview: 3. Find the molar volume of nitrogen at 35 °C and 45 MPa and the molar volume of
helium at 220 °C and 325 atm using the compressibility factor equation of state. Nitrogen Tc =126K PC = 33.5atm Tr=£=240 R=W_ﬂm____=13_3
126 0.101MPa 33.5~atm
From Figure 5.44 2 = 1.3
3 I
V=l.3><—2—2'4—m—M—ﬂ=0.073m3/km01
kmol 450atm 273
Helium I; = 5.26K PC = 2.26atm
Tr: 53 =4.0 P, = 325 =32
5.26+8 2.26+8
From Figure 5.44 2 = 1.6
I 3 D
V=1.6x£4__m__lm_m£=o,021.m3/km01
kmol 325alm 273 g 2. A stream of oxygen at 75 °C and 9.4 atm ﬂows at a rate of 375 kg/h. Use the SRK
equation to estimate the volume ﬂowrate. Oxygen Data a) = 0.021 TC = 154  K PC r= 49.7  atm Calculate SRK Parameters 2
a = WWW = 1.37
49.7
b = 0.086649% = 0.0220
49.7 m = 0.48508 +1.55171(0.021)— 0.1561(0021)2 = 0.518 T, =ﬁ=129
154 a =[1+(0.518)(1—J1’E) = 0.866 SRK Equation P: {if _ . (35a =(0.08206)(198)_(0.866)(1.37 =94
V—b VlV+bl V—0.0220 VV+0.022 Find the roots by Newton’s method. f(V)= (0.08206)(198) (0.866)(1.37) 16.2 1,19 A — A . ——9.40=‘—————— A A —9.40=0
V—0.0220 VlV+0.022l V—0.0220 VlV+0.022l f'lﬂb 16.2 +1.19l21}+0.022l (V — 0.0220)2 [1?(1? + 0022)]2
Start with the ideal gas value. ~ = ﬂ = (0.08206X198) Vl =1.73m3 /km01
P 9.4 A . . V
V2 44—51;1 =—1.511
1 Iteration gave 1.68 m3/kmol ...
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 Spring '14
 DBarkey
 Chemical Engineering, compressibility factor equation, Tc =126K PC

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