Compressibility Example - 3 Find the molar volume of...

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Unformatted text preview: 3. Find the molar volume of nitrogen at 35 °C and 45 MPa and the molar volume of helium at -220 °C and 325 atm using the compressibility factor equation of state. Nitrogen Tc =126-K PC = 33.5-atm Tr=£=240 R=W_flm____=13_3 126 0.101-MPa 33.5~atm From Figure 5.4-4 2 = 1.3 3 I V=l.3><—2—2'4—m—M—fl=0.073-m3/km01 kmol 450-atm 273 Helium I; = 5.26-K PC = 2.26-atm Tr: 53 =4.0 P, = 325 =32 5.26+8 2.26+8 From Figure 5.4-4 2 = 1.6 I 3 D V=1.6x£4__m__lm_m£=o,021.m3/km01 kmol 325-alm 273 g 2. A stream of oxygen at -75 °C and 9.4 atm flows at a rate of 375 kg/h. Use the SRK equation to estimate the volume flow-rate. Oxygen Data a) = 0.021 TC = 154 - K PC r= 49.7 - atm Calculate SRK Parameters 2 a = WWW = 1.37 49.7 b = 0.086649% = 0.0220 49.7 m = 0.48508 +1.55171(0.021)— 0.1561(0021)2 = 0.518 T, =fi=129 154 a =[1+(0.518)(1—J1’E) = 0.866 SRK Equation P: {if _ . (35a =(0.08206)(198)_(0.866)(1.37 =94 V—b VlV+bl V—0.0220 VV+0.022 Find the roots by Newton’s method. f(V)= (0.08206)(198) (0.866)(1.37) 16.2 1,19 A — A . ——9.40=‘—————— A A —9.40=0 V—0.0220 VlV+0.022l V—0.0220 VlV+0.022l f'lflb 16.2 +1.19l21}+0.022l (V — 0.0220)2 [1?(1? + 0022)]2 Start with the ideal gas value. ~ = fl = (0.08206X198) Vl =1.73-m3 /km01 P 9.4 A . . V V2 44—51;1 =—1.511 1 Iteration gave 1.68 m3/kmol ...
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