ME345_Lecture_18

# ME345_Lecture_18 - • Frequency f 1 = 115 Hz amplitude A 1...

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M E 345 Spring 2008 Professor John M. Cimbala Lecture 18 02/25/2008 Today, we will : Finish reviewing the pdf module: Fourier Transforms, DFTs and FFTs Do some example problems – FFTs Discuss leakage and the analogy between Fourier series and FFTs Review the pdf module: Windowing with FFTs Do some example problems – FFTs and windowing Example Given : A voltage signal contains two periodic components:

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Unformatted text preview: • Frequency f 1 = 115 Hz, amplitude A 1 = 2.00 V • Frequency f 2 = 180 Hz, amplitude A 2 = 0.500 V We sample the signal digitally at 1000 Hz, taking 256 data points. ( a ) To do : Is there any aliasing? ( b ) To do : Sketch the frequency spectrum and calculate the frequency resolution. ( c ) To do : Discuss how to improve the frequency resolution. Solution :...
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## This note was uploaded on 07/23/2008 for the course ME 345 taught by Professor Staff during the Spring '08 term at Penn State.

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ME345_Lecture_18 - • Frequency f 1 = 115 Hz amplitude A 1...

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