ME345_Lecture_32

ME345_Lecture_32 - M E 345 Spring 2008 Professor John M....

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
M E 345 Spring 2008 Professor John M. Cimbala Lecture 32 04/04/2008 Today, we will : Finish reviewing the pdf module: Dynamic System Response (2 nd -order systems) Do some example problems – second-order dynamic systems If time permits, start to review the pdf module: Temperature Measurement Example Given : The following second-order ODE: () 2 2 51 0 0 0 dy d y yx t dt dt ++ = The forcing function is a step function (sudden jump): x ( t ) = 0 for t < 0 x ( t ) = 25 for t > 0 ( a ) To do : Calculate the natural frequency and damping ratio of this system.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 5

ME345_Lecture_32 - M E 345 Spring 2008 Professor John M....

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online