ME345_Lecture_32

# ME345_Lecture_32 - M E 345 Spring 2008 Professor John M...

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M E 345 Spring 2008 Professor John M. Cimbala Lecture 32 04/04/2008 Today, we will : Finish reviewing the pdf module: Dynamic System Response (2 nd -order systems) Do some example problems – second-order dynamic systems If time permits, start to review the pdf module: Temperature Measurement Example Given : The following second-order ODE: () 2 2 51 0 0 0 dy d y yx t dt dt ++ = The forcing function is a step function (sudden jump): x ( t ) = 0 for t < 0 x ( t ) = 25 for t > 0 ( a ) To do : Calculate the natural frequency and damping ratio of this system.

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ME345_Lecture_32 - M E 345 Spring 2008 Professor John M...

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