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ps2_soln - EB 350 PPoHQm $2,“ 2 SoIv-élbqs Ell-3 Fay“...

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Unformatted text preview: EB 350 PPoHQm $2,“: 2. SoIv-élbqs Ell-3 Fay“ 200T Pr o\o\e m S ' USM3 KVL'. 80:) ‘—" V'Lt) + VLHQ (I) - Us"? thQ— brawn/k I‘dxiiomk‘é “RV 0v C‘V'MVEDP‘ (Z) (3) 2- 1‘? the. mitwfl. .shov'L‘A eke. SJJEQM £5 Z-E-Y‘OJ {:an 0926.30J Glni. the. resvlemfl PQSfo/DQ— 7s dug-E Jug, '5) “612 I—C ’UAQ, Inf-wt $015) 35 2:240 'Fov‘ a.“ Va—LAJ 0“: am?! tLDQn ’tLQ. VOA/Hwy rQ/SPOOSQ/ 73 JUQ. “to m [ll/hora filly-{2.3: gzafii) ”' OC— 1' Q 'tZ—oa $2 64050. a (‘63 :3 643‘", Ct) 72! (13> the. flew/7,4931% fro/9% )loLg ES 350 Problem 52.4. 2 5.1.,15905 —z- PPOL‘QM S 3' To be 2€rov{flw‘& Qinwg Superpofi'étén rnva‘l.” boLQ baéween 8.0“)“ mu'L‘uQ 543551 anal tkrz. Zero-unpd; méflame. 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'Y'G'Hfl =- D 352(42): £74,: StgfiCC)6eT PAH?“ co Mo'eQ. {ha/E t QQ‘E :‘C—‘T— g L L P yaw: <. ,. “mg: M pzvoo~T ’7‘ : .L +4. t fl c. c» 16 @ch '00 In CompanSonl t—T 325%”): éfiéfi {*(flft ‘39ch 5L; (,L—s = 3%; (29%)} 1W5 t0 J—~ In ovflav‘ '50 (on/)V'ée. 9125 (+30) ; C4 + CL 3 +(C\£C) wQ. Must How @142 Value, % the M/«Z? -F(~/:) ‘pov' “witL'f'O, 9:19- So ”U0, say-Lem LS COLVSU‘Q' -_ Cd‘s been) nob rebuke hwpflf‘ ME Ct,” (“REV/’6 age/avg an fowl: wok/05% the M/k'é). Prouem 5d ’2. So’v-Elon) -52 ‘l: -I: (Ljfiftkat + @Jfi'cldflt {- 70 cc, 1334:) + 6» WM) ‘5 <0 8063. EE 35-0 PrdHQ/n 3% Z go’s/bolls Pro b\e m 6 o sags-4:29" I 15 'Etm-Q. ~Vc2~v%}0¥ , coflJuQQr‘ 15L?— rosrmnsvas We» ——9I::7——>g '9‘“ 15 Ma .-. ac ”a; .7) 4:?» g (t: E 5:? 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(t)&(-l:+ chT, Sflfce ‘ 2 m 2 IS Eero—s‘tw 6 Qmear- beCau/SQ/ S 2 poS‘Zu v r l 04 M91: 9 £666 mote thcaé C(22) — 0° fi‘ _. a §,£¢‘F Cc.) 4' I; ‘9 (2’)]5 65+ Chgg EE are Phobia," 52,75 2. sold/gas ,m, ProHem G 2' W- oroaQr ‘50 (ethic/[i BQ/ couJJQ, fv‘bur‘q' Vex/[Ma‘s % fiw lflfldfij t—LQ’ I; fgem 51 all ACLm‘C’ o probla m 7 I- We, 0J9, wen thw'l: d (b) )5 m fim-A'Exé. response generwgoq/ % the ”VI/'5 F561 (52, Garage, tko, 5C7 Item 35 L-TIJ ft fo/{om thu’é the Hype 4, H5) 2 43%) «406—2) {22’ tLL fiefo’j’éu'k. (‘le an IQ, ‘ C-b) : (a -&Ift~23. ‘1. EE 350 Probbm Seé 2 pf‘oHQ/‘fl 7 2" 30:) —&L CL— -2) \ BQ, CW5¢ the. éds'tenq L5 ‘15 do, tero’otwée, (25/0 rue, ‘3 ole/fit; 05 LTtr-‘J <2an 3 at) ‘50 FLt; [47143 = ~24 6th) ~24 C‘E)‘ -1]- E E 35° Phob‘e m Sejé L SOL/1210105 " l2 —- EE 35° Preblem Sail: 2 sciatic»: —/3~ PM Hem ‘7 1' (5)73 ng\&S 1:51:29. \“OO‘tSel (Recall tL’m/"E l—Lt— : + Z or -2) 42cm QquplQ.) USQ, tke, 'QP-C'E W fi-E yaw—n) é : e. :3 8 J‘ /) Mayer J.— (670%: iegCWz-Jtznnjs : e (“Q Can JQnQrw‘LQ. th three, feats & VJ)? {other Ver y» n ”ma Opd/O/(Cwé r0015}. 75 ab": lb 77‘ “ 51(1ng .2?) fi=~lJ 0) +1 ' —-l‘1- EE 350 Probkgm Set 2. Sw/U‘EIO’U PTO Ham (7 m /X 0 get; 2. When mu/fitpdlfli an anfig (‘a F0 I) m \ v If? 75 Qahgk WovL wt’t‘) tho—IV Fold FQP‘résen‘A'w'Econ. Uélfl? 'L’. Q, a 477/2, 617V v EE 3so Problem 59,19 2 when; _,S_ ePoUem 0/ 3. Let 5:6“?ng karv, a an [o are, PeaQ 09,4959”. (0*) 5 .53" :: (a +3» (,a—ava z 6'1 4' 192 =IS'1 _. 20V 1: ZRzZSS ’ (53 5+ 5*“ : (a+d,tb)+(avgb) yb ; (521m 253 Cc) .S 25* = (“7‘97 “(Q'JH : 21.3 2W" Let 5:: IS\ e’L 3 LL: I‘Lleffll": r=|rléflL J mug. W: lwle‘f'x'wJ then m, ' 454nm 5 UL _. “Jada“ lwle’d’ _ ISI [\M g( ’N'X-W v w ’ vaeaLW lwlef‘w ' W' 'W’ 9mg So %9 ’6L9 8 4— a :3 2 C056 0V ?_9 -5Lé c055 : W 2—- (b) From (3% wrth sag/0L9; 5 «5* — 21m $1: HMO/So 8%6'8 fiLe :JZ 5lné or _ 9 9 smé :— €7L "’ €- #- (beau/SQ 0C) WJ anfl ‘15 romp/Q >3 EE 35o pflob‘em LI. m.) Prouem 52;]; z SoL/‘L‘Léns —I 7- a A COSW-L + GSInw‘l: W --W fiw'b_ “fa/t = ”<2 ’ 3+ ML?) : 3'5”??th “7:04 7m?” 9W? the. ram/H“ ~Fr=m L(Cc) wot—h c = Fifi—3L0 dvvJL 0(- :o to 054mm A (:05 w-l: + Esmw": 7- [H- +d‘fil C05 (v1: 4- X. (47(5)) (Se/Cause. W V481 _ —/§__ 23.0).20’) ; TaflI—A‘ = ’Tan .4» / u ID ;1 1. an N A- COJW't + BS/flw'e : GAL-+6; (05(w't‘ "Tq/f’B/iq) E E 350 Frame an $22!: 2. SOL/“Eton; —- ’39.. Pro b\Qm I0 I. T/RQ sem‘molon SufFVQJ-Yes [arm-Am} cupéer- an 8Ypr055mn 0" Sfibmen'fi Z, )t= ,anspoufl. C0J 6*9/1); —.g t LS 0K. le00 row vecévr >a.:’ 22* Embed) 2) a. 75 a. {x loo row veb'EW > X :- b‘kcoslt‘NJ :7) x LS ck. (x (oo rOw ueg'éow 3, TRQ. (ommaN—Q ‘ I > t : Qtn5,o\_c-Q. (O) IOV‘PLJ 1000)) ‘H'm; kegs [000 “A“ generm‘L‘fi a, vac/£0? t 4mm rows me. \ Column) w: {3" va. {vej (uni ”(”7 o to 1017', TL; transpom 302"» 0"; 2 is nQaQQQ because. QiflSfloLLQ. (Ca, 10*fcllooo) flroi/ca ”v l X loco row Ve V'Eor, Ll. \"‘ Y, :5 Syecl‘cwb 0L. .SO\\<Q/ fia£ Curve, \.~.gl =7 spec‘£(e> ox. oeaékrpofi fire—2n CerQ. 6“ T/ue Co mmamQ- holrQ. on Rows {3km Cur/‘efl'é V [at S o tha£ Sub sagqerre ; rap/1,”; Comma/pg oLjL ‘50 the, .tKLS'E‘y ()(o'é [7:613er than J f—Qp\a.cly It. 6. 7T/RQ, mv‘E’Q, 7.5 prangaflz on Faye IZ 67/11,- bl-Q. 07’0"? i5 awe/7 on [74%, 20. E E 350 Prob‘em Se'é Z Sohfbmg % EE 350 Problem Set 2, Problem 10, Part 6 % Name: Section: % generate a time time vector t = linspace(0,5); % construct the signals x and y y = exp(—t) .* cos(2*pi*t); x = exp(—t) .* sin(2*pi*t); % plot the signals figure(l) plot(t,y, '—r', t,x. '—.g' ); legend('y(t) = eA{—t} cos(2 \pi t)',... 'x(t) = eA{—t} sin(2 \pi t)') ylabel('Signal Amplitude') Xlabel('time [S]') title('Problem Set 2, Problem 10, Part 6') gtext('Name: ') gtext('Sec: ') — m,“ EE .3527 Signal Amplitude Frame/m 80:19 2 Solu£IM$ —- 20.. Problem Set 2, Problem 10, Part 6 — y(t) = e't cos(2 n t) x(t) = e't sin(2 n t) timé [s] ...
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