EES_Solution_Minor_losses_example_problem

EES_Solution_Minor_losses_example_problem - EES Solution...

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EES Solution for Example Problem – Major and Minor Losses in a Piping System Here is exactly what I typed into the main “Equations Window” of EES: "EES Solution for the class example problem - major and minor losses in a piping system J. M. Cimbala, February 2005" "Constants:" h_L = 35 [m] rho = 998 [kg/m^3] mu = 1.00e-3 [kg/(m*s)] D = 0.025 [m] L = 20.0 [m] SigmaK = 13.35 "Equations:" h_L = (f*L/D + SigmaK)*(V^2)/(2*g#) "Note that g# is the gravitational constant, pre-defined by EES" Re = rho*D*V/mu eps_by_D = 0.004 V_dot = V*PI*(D^2)/4 "Colebrook equation:" 1/sqrt(f) = -2.0*log10(eps_by_D/3.7 + 2.51/(Re*sqrt(f))) Note: We could have used the EES function “MoodyChart” instead of the Colebrook equation; i.e., f = MoodyChart(Re,eps_by_D) "To solve, click on Calculate and then Solve. Note that it does not converge unless you change the limits and
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This note was uploaded on 07/23/2008 for the course ME 33 taught by Professor Cimbala during the Fall '05 term at Pennsylvania State University, University Park.

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EES_Solution_Minor_losses_example_problem - EES Solution...

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