CAPA 5 - gaitons Set 5 Due Fri Mar 7 2008 at 23:59 1 1[1 point 10 tries A 22.2 kg child is on a swing that hangs on the bottom of two 1.87 m long

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Set 5, Due Fri, Mar 7, 2008 at 23:59 1. 1 . [1 point, 10 tries] A 22.2 kg child is on a swing that hangs on the bottom of two 1.87 m long chains. What is the maximum speed if she swings out to a 41.4° angle? Answer: 3.03e+00 m/s 2. 2 . [1 point, 10 tries] A package of mass 8.9 kg is released from rest at a warehouse loading dock and slides down a 6.8 m high frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 17.8 kg from the bottom of the chute. Suppose the packages stuck together. What is their common velocity after collision? Answer: 3.85e+00 m/s 3. 3 . [1 point, 10 tries] A new event has been proposed for the Winter Olympics. An athlete will sprint 50.0 m, starting from rest, then leap onto a 23.5 kg bobsled. The person and bobsled will then slide down a 40.0 m long ice- recovered ramp, sloped at α=25.0°, and into a spring with a carfully calibrated spring constant of 1573.0 N/m. The athlete who compresses the spring the farthest wins the gold medal. Jennifer, whose mass is 53.0 kg, has been training for this event. She can reach a maximum speed of 14.2 m/s in the 50.0 m dash. How far will Jennifer compress the spring? Answer: 4.56e+00 m 4. 4 . [1 point, 10 tries] A 55.7 g ball of clay hits and sticks to a 2.35 kg block sitting at rest on a frictionless surface. What is the speed of the block after the collision if the initial speed of the ball of clay is 4.91 m/s? Answer:
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This note was uploaded on 07/23/2008 for the course SCIENCE PHYSICS 1B taught by Professor Hughes during the Winter '08 term at McMaster University.

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CAPA 5 - gaitons Set 5 Due Fri Mar 7 2008 at 23:59 1 1[1 point 10 tries A 22.2 kg child is on a swing that hangs on the bottom of two 1.87 m long

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