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Unformatted text preview: Taking a Shower while Someone Flushes the Toilet (Example Problem 89, engel and Cimbala) This is a practical, everyday example of a parallel piping network. This is a simplifying assumption that may or may not be valid. We should check the validity later. We consider only the cold water line. The hot water line is separate, and is not connected to the toilet, so the volume flow rate of hot water through the shower remains constant. The cold water, however, is affected by flushing the toilet. Part (a) is not a parallel system since no flow through the toilet. We neglect the velocity heads in the energy equation. Alternatively, if V1 = V2, then these two terms cancel each other out. P2 = Patm, and therefore P1 P2 = P1,gage. Colebrook equation Answer to part (a) no toilet flushing This is where EES comes in handy solving all these simultaneous equations! Now we need three Colebrook equations one for each branch! ...
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This note was uploaded on 07/23/2008 for the course ME 33 taught by Professor Cimbala during the Fall '05 term at Penn State.
 Fall '05
 CIMBALA

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