Lecture 20 sect 9.8

Lecture 20 sect 9.8 - xy A I xydA = - xy x y o o I I x y A...

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ME 221 Lecture 20 1 ME 221 Statics Lecture #20 Sections 9.7 - 9.9
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ME 221 Lecture 20 2 Homework #7 Chapter 4 problems: Chapter 9 problems: Due Today
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ME 221 Lecture 20 3 Homework #8 Chapter 9 problems: Chapter 5 problems: Additional information to be on Angel Due Friday, October 24
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ME 221 Lecture 20 4 Product Moment of Inertia Basic section with two axes of symmetry x y Composite sections - product parallel axis theorem
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Unformatted text preview: xy A I xydA = - xy x y o o I I x y A =-ME 221 Lecture 20 5 Mohrs Circle for Principal Inertia +I xy-I xy I xx , I yy I yy x I xx I xy x draw point ( I xx , I xy ) and the circle ( I xx +I yy )/2 draw circle center ( I xx + I yy )/2 x I MAX I MIN 2 use geometry to find I MAX , I MIN and Angles in Mohrs circle are twice those in the section analyzed. ME 221 Lecture 20 6 More Chapter 9 Examples...
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Lecture 20 sect 9.8 - xy A I xydA = - xy x y o o I I x y A...

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