This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: F F11 = 0 therefore F12 =1. 98953 . 1 010472 . 21 22 12 2 1 21 = − = = = F F F A A F Setting up radiosity equations ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ ′ ′ = ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ − − − 4 2 2 4 2 2 1 2 1 22 2 21 2 12 11 / 200 1 1 T DL T q J J F F F F π Inverting and solving for J’s D L ME 410 Spring 2008 ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ = ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ 84 . 3524 94 . 6707 2 1 J J Solve for T 1 K J F J T 45 . 592 4 1 1 2 12 1 1 1 = ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ − = σ ε ρ...
View
Full
Document
This note was uploaded on 07/25/2008 for the course ME 410 taught by Professor Benard during the Spring '08 term at Michigan State University.
 Spring '08
 BENARD
 Heat Transfer

Click to edit the document details