# TRM-Section 11.2 Full Solutions - DO NOT POST THESE ANSWERS...

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DO NOT POST THESE ANSWERS ONLINE© BFW Publishers 2014The Practice of Statistics for 5/e3.()()()()()()22222225577.567653.44215220.25157151.7577.5653.44220.25151.75640612.19394421.8119.49612.19421.81χ=+++++=4.With df = (3 – 1)(2 – 1) = 2, theP-value is less than 0.0005. Using technology,P-value =2χcdf(lower: 19.49, upper: 1000, df: 2) = 0.000059.5. Assuming that there is no difference in the distributions of Facebook use between students onPenn State’s main campus and students at Penn State’s commonwealth campuses, there is a0.000059 probability of observing samples that show a difference in the distributions of Facebookuse among students at the main campus and the commonwealth campuses as large or larger thanthe one found in this study.6.Because theP-value of 0.000059 is less thanα= 0.05, we reject0H.There is convincingevidence that the distribution of Facebook use is different among students at Penn State’s maincampus and students at Penn State’s commonwealth campuses.Check Your Understanding, page 711:1.The bar graph shows the conditional distribution of quality of life for Canada and the U.S.2.State:We want to perform a test at theα= 0.01 level of0H: There is no difference in thedistribution of quality of life for patients who have suffered a heart attack in Canada and the U.S.

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