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# ProbSet3s - ME 416 Computer Assisted Design of Thermal...

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1 ME 416 Computer Assisted Design of Thermal Systems Practice Problems #3 Thermal Environmental Engineering, Engineering Economics, and Air/Water Vapor Systems 1. The heat flux is given by & ′′ ′′ q = T - T R i,s o,s tot , where ′′ R tot is the total thermal resistance for the wall on a per area basis. It is given by ′′ R = k + (.15)k + (.85)h + k + k tot pb pb ws ws ag -1 hs hs vs vs δ δ δ δ . Evaluating the resistance with the values provided, gives ′′ R = 0.17 + (.15)(0.14) + (.85)(1.5) + 0.094 + 0.20 = 0.795 (m K) / W tot -1 2 0 01 010 0 005 0 002 . . . . Now calculating the heat flux & ′′ q = 30 - 18 0.795 = 15 W / m K 2 2. Our total resistance now changes to ′′ R = k + (.15)k + (.85)k + k + k tot pb pb ws ws ins ins -1 hs hs vs vs δ δ δ δ δ Using the values provided gives ′′ R = 1.697 (m K) / W tot 2 and a heat flux of 7 W/m 2 K.

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ME 416 CAD of Thermal Systems 2 3. We perform an energy balance on the wall, which yields, Solar Absorbed + Heat from Inside = Heat to Outside or mathematically α sol sol i o,s i o o,s o q + T - T R = h (T - T ) & ′′ ′′ Solving for T o,s gives T = q + T R + h T 1 R + h = + 298 1.0 + (38)(283) 1 1.0 + 38 = 290 K = 17 C o,s sol
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