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Unformatted text preview: oil as a function of temperature and pressure using the density and specific heat relations given below. c P = 0.67505 + 4.3156 x 103 T  1.498 x 106 T 2 + 2.7403 x 109 T 3 in kJ/kg ⋅ K ρ = 1037.3  0.38658 T  5.7951 x 104 T 2 + 5.384 x 107 T 3 in kg/m 3 Temperature (T) in Kelvins ME 416 CAD of Thermal Systems 2 5. Reduce the following thermodynamic partial derivatives. (a.) s v h ∂ ∂ (b.) h T s ∂ ∂ (c.) u P T ∂ ∂ (d.) v T P ∂ ∂ 6. Evaluate the partial derivatives in problem #5 for an ideal gas. 7. Using a least squares approach generate a power law equation (Nu = aRa n ) for the following data. Rayleigh Number (Ra) Nusselt Number (Nu) 5 x 10 3 5.18 1 x 10 4 6.25 3 x10 4 8.41 7 x 10 4 10.57...
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 Fall '07
 SOMERTON
 Convection, Heat, Nusselt number, Rayleigh number, Thermal Systems

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