Exam3s - Spring 2006 Thermodynamics Exam #3 Solution...

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1 ME 201 Thermodynamics Exam #3 Solution Problem 1 Steam at 0.5 MPa and 350 ° C is used to fill a 0.1 m 3 tank, which is initially empty. After filling, the tank is cooled to 50 ° C and the contents become saturated liquid. Determine (a) the heat transfer required (b) the mass of water added to the tank Solution: System Type: Transient Working Fluid: Compressible Process: Constant total volume State 1: Fixed State 2: Fixed State 3: Fixed W bnd = 0 W sh = 0 Q=??? conserv. of mass: m 2 = m 3 1 st Law: m 2 u 2 = m 3 h 3 + Q State 1 (initial) State 2 (final) State 3 (inlet) T 1 T 2 = 50 ° C T 3 = 350 ° C P 1 P 2 = 12.352 kPa P 3 =0.5 MPa u 1 u 2 = 209.33 kJ/kg h 3 = 3168.1 kJ/kg m 1 =0 kg m 2 = 98.81 kg m 3 = 98.81 kg v 2 = 0.001012 m 3 /kg Italicized values are from steam tables. Bold values are calculated. Approach: We go to the steam tables and read the remaining properties fr states 2 and 3. The mass in final state can then be calculated from V 3 /v 3 . Finally the first law is
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This note was uploaded on 07/25/2008 for the course ME 201 taught by Professor Somerton during the Spring '06 term at Michigan State University.

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Exam3s - Spring 2006 Thermodynamics Exam #3 Solution...

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