HW5 - b Helium at 3200°F and 1.3 atm goes isentropically...

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Spring 2006 1 ME 201 Thermodynamics Homework #5 Due Wednesday, February 1, 2006 1. Calculate the entropy change for N 2 as it goes from 250 K and 1000 kPa to 1300 K and 60 kPa. 2. For the two processes given below, determine the final temperature, pressure, specific volume, and the changes in internal energy, enthalpy, and entropy. a. Air at 8400 R and 66 psia goes isothermally to 1.7 psia.
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Unformatted text preview: b. Helium at 3200°F and 1.3 atm goes isentropically to 435°F. 3. Calculate the final temperature and change in specific internal energy as magnesium at 30 psia and 500°F goes insenthalpically to 90 psia. 4. Determine the changes in internal energy, enthalpy, and entropy as liquid petroleum at 70 kPa and 300 K goes to 100 kPa and 430 K....
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This note was uploaded on 07/25/2008 for the course ME 201 taught by Professor Somerton during the Spring '06 term at Michigan State University.

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