HW16 - refrigerator to produce a low temperature heat...

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Spring 2006 1 ME 201 Thermodynamics Homework 16 Due Monday, 3/27/2006 1. Consider a power plant that is producing 1 MW of electric power as it operates with a high temperature of 1800 K and a low temperature of 290 K. If we can sell the electric power for $0.04 per kW hr, and the heat transfer from the high temperature reservoir costs $0.0075 per kW hr, what is the maximum income per year the plant can generate? 2. It is clear that we can improve the efficiency of a heat engine by lowering the temperature to which the heat rejection occurs. One way to achieve this is to use a
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Unformatted text preview: refrigerator to produce a low temperature heat reservoir. It is proposed to do this to the power plant of problem #1, lowering the low temperature reservoir to 240 K. If the power plant is till produce 1 MW of electric power, what is the maximum income per year the plant can generate? Remember to include the power requirements of the refrigerator in this calculation. The high temperature heat reservoir for the refrigerator is at 290 K....
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This note was uploaded on 07/25/2008 for the course ME 201 taught by Professor Somerton during the Spring '06 term at Michigan State University.

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