Engineering Mechanics Statics - Intructor Solutions manual 2.46 - 246 If the magnitude of the resultant force acting on the bracket is 600 N directed

# Engineering Mechanics Statics - Intructor Solutions manual 2.46

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This preview shows page 1 out of 1 page. Unformatted text preview: 2—46. If the magnitude of the resultant force acting on the bracket is 600 N, directed along the positive u axis, determine the magnitude of F and its direction (1). SOLUTION Rectangular Components: By referring to Figs. a and b, the x and y components of F1, F2, F3, and FR can be written as (F1)x = F1005¢ (F1)y = Flsin¢ (F2)x = 650G) = 390N (F2)y = 650 (g) = 520N (F3)x = 500 cos 45° = 35355 N (F3)y = 500 cos 45° = 35355 N (FR)x = 600 cos 45° = 424.26 N (FR)y = 600 sin 45° = 424.26 N Resultant Force: Summing the force components algebraically along the x and y axes, we have is 2(FR)x = EFX; 424.26 = F1 cos d) — 390 + 353.55 (1) F1 cos (b = 460.71 +lE(FR)y = EFy; 424.26 = F1 sin¢ + 520 — 353.55 (2) F1 sin ¢ = 257.82 Solving Eqs. (1) and (2), yields ¢ = 29.2° F1 = 528N Ans. ...
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• Spring '16
• DR.Khan
• Statics, Force, 45°, resultant force, F3, 29.2°, 650G

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