Engineering Mechanics Statics - Intructor Solutions manual 2.49 - 249 If the magnitude of the resultant force acting on the eyebolt is 600 N and its

# Engineering Mechanics Statics - Intructor Solutions manual 2.49

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This preview shows page 1 out of 1 page. Unformatted text preview: 2—49. If the magnitude of the resultant force acting on the eyebolt is 600 N and its direction measured clockwise from the positive x axis is 6 = 30°, determine the magnitude of F1 and the angle &lt;1). SOLUTION Rectangular Components: By referring to Figs. a and b, the x and y components of F1, F2, F3, and FR can be written as (F1)x = F1 COS d) (171)}, = F1 sin (1) (F2): = 500 cos 60° = 250N (102)y = 500 sin 60° = 433.01 N 3 4 (F3)x = 450(g) = 270N (F3)y = 450&lt;§&gt; = 360N (FR)x = 600 cos 300 = 519.62N (my = 600 sin 30° = 300N Resultant Force: Summing the force components algebraically along the x and y axes, i&gt; 2(FR)x = EFx; 519.62 = F1 cos o + 250 — 270 F1 cos d) = 539.62 (1) +TE(FR)y = 213; —300 = F1 sin¢ — 433.01 — 360 F1 sin ¢ = 493.01 (2) Solving Eqs. (1) and (2), yields (1) = 42.4° F1 = 731 N Ans. ...
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• Spring '16
• DR.Khan
• Statics, Force, Cos, Right angle, 30°, resultant force, F3

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