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Unformatted text preview: PHYSICS 231 INTRODUCTORY PHYSICS I Lecture 21 Simple Harmonic Motion ϖ , f, T determined by mass and spring constant A, φ determined by initial conditions: x (0), v (0) Last Lecture f = 1 Τ ϖ = 2π φ = 2π Τ x = Αχοσ(ϖτ φ29 ω= ϖΑσιν(ϖτ φ29 α= ϖ 2 Α(χοσϖτ φ29 ϖ = k m Example 13.3 A 36kg block is attached to a spring of constant k=600 N/ m. The block is pulled 3.5 cm away from its equilibrium position and is pushed so that is has an initial velocity of 5.0 cm/s at t=0. a) What is the position of the block at t=0.75 seconds? a) 3.39 cm Example 13.4a An object undergoing simple harmonic motion follows the expression, x ( t ) = 4 + 2 χοσ[π(τ 329 ] The amplitude of the motion is: a) 1 cm b) 2 cm c) 3 cm d) 4 cm e) 4 cm Where x will be in cm if t is in seconds Example 13.4b An object undergoing simple harmonic motion follows the expression, x ( t ) = 4 + 2 χοσ[π(τ 329 ] The period of the motion is: a) 1/3 s b) 1/2 s c) 1 s d) 2 s e) 2/ π s Here, x will be in cm if t is in seconds Example 13.4c An object undergoing simple harmonic motion follows the expression, x ( t ) = 4 + 2 χοσ[π(τ 329 ] The frequency of the motion is: a) 1/3 Hz b) 1/2 Hz c) 1 Hz d) 2 Hz e) π Hz Here, x will be in cm if t is in seconds Example 13.4d An object undergoing simple harmonic motion follows the expression, x ( t ) = 4 + 2 χοσ[π(τ 329 ] The angular frequency of the motion is: a) 1/3 rad/s b) 1/2 rad/s c) 1 rad/s d) 2 rad/s e) π rad/s Here, x will be in cm if t is in seconds Example 13.4e An object undergoing simple harmonic motion follows the...
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This note was uploaded on 07/25/2008 for the course PHY 231 taught by Professor Smith during the Spring '08 term at Michigan State University.
 Spring '08
 smith
 Physics, Mass, Simple Harmonic Motion

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