ANSC 3500 Exam 4 Biase - First Name l A(JlliY Q,Last Name...

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Unformatted text preview: First Name: l A (JlliY Q. ,Last Name: QQQW 2016/11/15 ANSC 3500 w AnEmal Breeding Exam iV - 64 points (351 Present the mathematical logic that led you to an answer wherever calculations are needed. U Please, indicate ifyaur calculations are on the back of a page. Multiple choicecircie onEv one answer. '- Ol L . L l 1. (2 points} The selection approach that usually targets one trait at a time, consecutively. a. index selection 30. independent culling andem selection . Random selection 2. (2 points) The selection approach that establishes minimum Standardefor each trait undergoing selection. 3. Index selection \' @ndependent culling c. Tandem selection d. Random selection 3, (2 points) Wis a genetic consequence of inbreeding: 3. Increase in dominance effect \ .lncrease in homozygosis c. increase in heterozygosis cl. Increase in breeding values 4. (2 points) is a genetic consequence of outbreeding: a. increase in dominance effect b. increase in homozygosis ncrease in heterozygosls cl. Increase in breeding values 5. (3. points) is (are) phenotypic consequence of inbreeding: a. Hybrid vigor \ b. $1 are expected to have better performance than the parents Phenotypes associated {a recessive aiieles will express d. Phenotypes associated to recessive alleles will be masked by dominant alleles e. A,B,C 6. {2 points) is (are) phenotypic consequence of outbreeding: a. Hybrid vigor b. F1 are expected to have better performance than the parents c. Phenotypes associated to recessive alleles will express \ d. Phenotypes associateci to recessive alleles will be masked by dominant alleles. @Afifi) 7. (2 g: ints) What is the measure of pedigree relationship? a. lnbreeding coefficient \ b. Phenotypic correlation @mefficient of relationship . Heterosis Page 1 of 6 First Name; ‘ A Q‘YQ‘ . Last Name: g9 “Eb 201611115 fitfiiiljfifimfldl‘slhgifi’réfita‘blé fifil‘élw, bléa'Sej "ca‘lwl'aite fihe wwwdc genfi‘leypric prugp'ortiuns for ting-bell genflafiten 3‘3 \0 mating between Marga number of individuals frqrn the breeds Large White and-Dumps?! Tabie i» "Frequencies cf the fuzz germ in diffemnt heads of gigs. Breeds No. Gene frccgumcy i M’Q‘JQJ IVE (Na) 1}}; (Nu) Large White 69 0.91‘ (78) {1092(3) _ Landmcc 85 3.55” {38) 0.435(31) - Woe l2 0.83 {10} U.16{2} w Pietraén 12 w 0315(9) (3.25 (3) _ ' Teas] 379 0.70 (£26) 02856) 0132 (3} 0‘ CH 4— 7; (0 C350 , 0-‘1 {5— ' , o S NN — “manual homazygutus; Ni: - hemozygotes; m: - massive homozy- i/L L O. 0’13 - G Ll aotesfl-Wfifferemlener means P «THE 0 ‘3 ?7 4- (y; ,, O 4119‘) a 0.011- Modified Ernm fiestas at al., 2000. ht:p:l! € ' ‘- E) 140 i m ' 0 0 Rubric ‘ Credits 3 Standards mm_ 7 , in calculations and answer are presented correctly, : L_ W 08 Minar“ calculatian mistake. ‘ 05 Major“ calculation mistake but wi [h correct thought grocess. ‘1 G incoriect thofignl process to solve the problem. Blank Space. * Minur or Major calculation mistakes will be defined at each pmbiem and ingjritena wlll be applicabée for all studants. 0.6? o. O-l'l Ci“ 0.50% ”l 9, (5 points) En general, traits having low heritability have high heterosis, and vice-versa. Please, briefly, explain the [0 basis of the inverted relationship between heritability and hetemsis according to the central quantitative genetic principle lP=g+BV+EE¥+ _ El . NM , _ , (N \S—éfi-‘Ffi-fifl‘ H‘Mflj 'W NVH’OHOIM M [MN \3 leukd An) hit-Yams??? maul w 3W. WW)“ Cw” EN" bu: i w M Mumm‘ biLN W“ mum». K [mm ihwcmu.‘ Pm! WE Muller/nap (5)00 is «m MM“ olmmfium. Page 2 of E First Name: E A0” I Q. 1 Last Name: RQMgh 2016/11/15 Rubrlc Credits S‘andards 10 Calcu‘atiuns and answer are presented carrectw‘ ‘ DB Mincr“ caEculation mistake. E 55 g Majm‘ ca‘culation mFstaka but with correct thought prams; U Incurrect thought process to soEve the problem. , Stank space. _‘ i * Minnror Major ca|cuiatinn mistakes will be defined at each prub‘em R and the criteriflgil! be app‘écable for 3N students. FN= '8 C K - F « a. ,E udiwvgfim F}; ‘ K’ F I) : [{YXCD" 0.11! i E Jr 9 0.0 \l‘r 3/ *oJ’f‘E , Ddfiblg Page 3 of 5 First Name: I A U“ i L J Last Name: Q Q Q!) 2016/11/15 6 11. Wfiéfififi?§éfififimrfiéfi”aha.fifirfiéfiéflflfififiwm¢mm§ufimm my wwfifi @Qcfixfi-fiéfimfiiflipfiammfifm. ' WW A k 1 1 "MEX 1+F W"! Racy 2 ZCA71{ /2) ( CA) E f/l—o—Fxxzrl-e-Fy wfi L/W‘ 'm hm" C ' 10 Ca‘mlatlnns and answer are presented corzentlv. US i ¢ Minor" caiculation mistake. [El B / 05 Ma;or* calmtatinn mistake but with currect thought process. 0 Incorrect thought process t0 solve the prob|em. Blank Space. ‘ Mina: or Majar :a‘wlatiun mistakes WW be defined at each prsblem and the criteria wfll be applicable for all students. ¥% ‘5 wt) ‘ d1) nfi LWQW vcuuv‘r Rubrk: __ "Credits“ 3 Standards o. 2 €>\1 57M Z . 2“(3.13mi " J1“) Page 4 of 5 First Name: (AQN I, , Last Name: E251 {ah 2016/11/15 fi’é‘ffié‘ F 31355 i BE 6? E33}? 12. Wfim‘t‘é \O ' 's’EEl’bf ’37; Red An‘rgu's; % Aegis; fillemfpni-tasifieswmpamfitamm . mamalmafisqutd, figpgu; TypéL-a! H individual-WWW vigbr‘for‘wea-némg weigh: is Mlb. Asayming'mev 4 Mmawwmmmwméds' éfi'éfifié'rl‘yffifi‘é‘lfi'f’éif ciaiwlaté fhéfififihfiflfl’é’fic’ié‘d’fl’éfilneflt in mis-cgpss. r , Ti REV = (3 ‘Zpsixi7m) ><F1Hl7 i=1 Rubrlz: Credlts if} Calculatiungand answerare presented correctly. OS Mlnor" calculation mistake. 05 O Malcr‘ calculation mlStEkE but witficorrect thought process. incorrect thought process ta solve the problem. Blank snace. * Minor ur Major calculation mistakes will be defined at each prubiem and the crllerla will be applicable far all qtudancs. cm 0/7. - 03 + m - V1) * (w - m -* Lo- m : on? 40.0915“ = O.\%’l§’ A /""‘- m: fiommcfix FHW r mangxquw ‘4 $533551 % Hal Page 5 of 6 3 l First Name: ( A a“ I 9. ,Last Name: ngk; 2016/11/15 Use the table beiow (Bourdon, 2006. Understanding animai breeding) page 339135 a reference for the next question again 9.1 Bfeed Cnmposition and $ercentage 0% ?1 Hybrid Vigor Rammed in Succesesive estimations of Two- and Three—Breed Spafiai Rotations Using Purabrad Sires“ WMWWW Twmamed finiat‘mn ‘ Threefireed Rotation % Bread 84. Breed Campssésion Compesifion Ganeratiera Breed of Sire A 8 % F. HV Bread 01 Sire A B C ‘34: F1 HV Foundation 3 O 189 G C i) 0 160 G 1 A 5E! 50 190 A 56 i} 58 130 2 B 25 75 so 5 25 50 25 lei) 3 A 63 37 ’75 C 13 25 63 75 4 B 33 69 63 A 56 13 31 88 5 A 66 34 69 B 28 56 16 88 a E 33 67 66 C 14 28 58 554 y A 66 3:1 6? A 57 14 29 86 3 B 33 67 66 B 29 57 1»; $6 9 A 67 33 67 C 14 29 57 - 86 19 B as 67 57 A 57 14 29 8f: 'flyhrid vigae' is assumed Iinearfiy {3331mm heterozggasizyy ”The breed of the faundafion éemales is aiso a sire breed in the magnum ’95. (5 point) In one sentence, what is the reiationship between the number of breeds used in a crossbreeding rotation system and fihe retained hybrid vigor? “Wu (brewer may hUmigM (3% 10mm WM \ m gnaw m Yemmx YinmA \(ilflw. Page 6 of5 ...
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