ANSC 3500 Exam 1 Biase - 2016/09f12 First Name(in A f ‘9...

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Unformatted text preview: 2016/09f12 First Name: (in A! f ‘9' , Last Name R1 a {M ANSC 35007 Animal Breeding Exam 1 . 100 points Circle letters on multipie choice questions. write your answers on the Eines whenever prese complete the tables with your answers wherever available. Present the mathematical logic that led you to an answer wherever calculations are needed. Muitipie choice ~ Circle the correct answer (1 points each) 1. What is any observable or measurable characteristic of an individual called? 3. Biological Type b. Environmentai Effect c. Phenotype Trait 2. A loci having different DNA sequence is known as: a. Homoiog Hate rozygote C. Homozygote d. Allele 3. A loci having same DNA sequence is known as: a. Homoiog b. Heterozygote @‘3 H o m ozygote a: Ailele , 4. What is the name of thefprocessttfi‘at produces gametes in mammals? a. Mitosis b. Gene Assortment g) Meiosis . GeneSegregation 5. What is an observed category or measured level of performance in an individual called? a. Biologicai Type b. Environmentai Effect (53 Phenotype d‘. Trait 6. What is(are) key components of the process to improving performance in the next generation? .' a. Selection in. Mutation c. Mating d. Migration @ A&C f A&D 7. What are the assumptions of Hardy—Weinberg Equilibrium a. Popuéations undergoing seiection, mutation, migration and genetic grift Large populations, random mating and no forces affecting gene frequency 5. Selection and mating of parents at. independent Assortment and Segregation Page 1 0f 5 First Name: EA! Zir‘. ,Last Name '1; a 0‘ 2016/09/12 8. Which oithe following combination of markers is Fill in the blank [1 points each) 9. 10. 11. 12. 13. 14. 15. 16. Given the linkage map for chromosome 1 in caitie (Bishop et alw 1994) shown on the figure below in this image, the length of the chromosome is measured in centiMorgan (CM), and the numbers bellow the line are estimated distance between loci. $51.9 CM less susce tible to recombination during gametogenesis, a. AGLAl'.’ and RMDBS b. ILSTSOD4 and iNRADll ' c.‘, 332724 and BM864 HWL U‘OW «'99 C‘WW RMDBS and BLZS ., K— nim osmium inc {fly-W “:0ij 1 ml in 5) 04M I I L The type of inheritance by which the expression of the heterozygote is exactiy midway of the homozygous genotypes. gig M“ “ii A The type of inheritance by which the phenotypic expression is limited to one sex. gii' iii" 5 )1 (M is E h! flflu The type of inheritance by which the expression ofthe heterozygote is identical to the expression of the homozygous dominant genotype. ‘g C An interaction among genes at different loci such that the expression of genes at one iocus is dependent on genes present at one or more other loci. 93% “ kg “Iii lg Q The type of inheritance by which the mode of gene expression differs based on the sex of the individual. [RV n. The type of inheritance by which the expression of the heterozygous more closely resembles the homozygous dominant genotype. 1 N! A l g E ii I}! IS Ali; fl 1 The type of inheritance by which the expression ofthe heterozygote is outside the range defined by the expression of the homozygous dominant genotypes. ix [\“k A A The type of inheritance by which the mode of gene expression is based on genes residing on the sex chromosomes. Page 2 of 6 Vi Flrst Name: CJGAYE , Last Name igfiifin 2016/09/12 17. 18. 19. 20. 21. 22. %e “Qfl‘AJ EL The genetic makeup offihe individuai. H! ff (1! I 5% Vault The value of an individual as a parent. Assuming an arbitrary scale of phenotypic values below, place the genotypes A1A1,A2A2, AlAZ according to different types of allelic relationship specified. 10 15 20 25 30 M {1 point) A‘ A" / Dominance A1 ht As A1 (1 point) Overdominance A? A” _ m M M / r ...l (3. point) \ A A ‘ Cndomlnance A: mm—M/ (4 pts.) What is the basic model describing phenotype for sim ply inherited traits? Please, define all model components. 1 P : bl" E / . ,r l PNWML x EXNllrvnmufi 3WMW Page 3 of 6 First Name: i A!!! H E! i Last Name CLm 2016/09/12 23‘ [30 points) Assume a population under Hardy Weinberg equéiibrium with a distribution of individuais and p7 genotypes for locus A described in the tabie beiew. What are the expected genotypic frequencies in the next generation? A]. A1 A1 A2 A2 A2 Number ofindiuiduais 36 44 20 Frequency next gen. “,0 134-610 ' ‘8 100 w - 1003* 6‘, ('(A’D 7’00““ -: —%: (3,41 \: ?1*1pc\‘ q?- . ~ A AIA|H)1_ “/6 3314M 0'5 - 0.651 ~ 03“ 0.44517, wofh 0-“ L94 «1 9.1% Ami winch? e D. \8 Page 4 of 6 é‘ErstName: HOME ,LastName Eémb’n 2016/09/12 0 24. [20 pts.) Assuming 10 plglets per litter, lf 6 black boar (genotype il or ii) is mated to a group of Willie sows ’1, (genotype ll), how many sows are needed for you to be 99% confiéent that he does not carry the l allele? MW ”El (1: w_ ling (Vilm/ :«7, ____—.-——-—-—-r A), O ltflq : o . (ow 1» l q? 25. (20 pts.) Another black bear (genotype ll or Ii) in question is mated to 5 white sows [genutype ii) and 3 Berkshire black sows, The Berkshire black sows are knewn carriers of the 2 gene. StiEl assuming 10 piglets per litter, how confident areilfihu thafifi‘ls boar does not cara'y thei aElele? l K M v“) P®33=l*Ilwwfilflnmfiyflfl : l ’ lb «lfif’l‘: (@3637 = l * [mmmam * [email protected]"‘93 a: \- lfl‘bbxn)" % O.0l‘l”{6 T\ Page 5 Of 6 FlrstName: {MINE LastName SHAW 2015/09/12 25. (5 pts.) In sheep, expression of the allele for horns (h’l is a sex Influenced trajt. Males possessing one h“ 5 gene are horned, while it takes two h+ genes for a femaEe to be harmed. Dorset sheep are horned and the breed only contains the h” gene. Suffolk sheep are polled and have a genotype of hh. Two F1 DorseteSuffoEk progeny are mated. What propertion of the resulting ram {male} lambs would you expect to be polled*? Oa 1-" What proportion of the ewe (female) lambs would you expect to be pulled? O ; 1 6 *use two tiecimal digits M— 07' 'x n”; Q ~. \(lthafl mvw humid" 79/4 = 0.16 Puma ‘ Whoa? ‘L 'mem: ”Ll ‘ 0-25 PUllflAH Wvl '- U19 .5 : mm ._ n Page 6 of 6 ...
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